Total number of covalent bonds in `C_(3)O_(2)` is____
The total number of `sigma` and `pi` bonds present in the compounds are_______

Explanation

To determine the total number of covalent bonds in \( C_3O_2 \) and the distribution of sigma and pi bonds, we can follow these steps:

### Step 1: Identify the Structure of \( C_3O_2 \)
The molecular formula \( C_3O_2 \) indicates that there are three carbon atoms and two oxygen atoms. The structure of carbon suboxide can be represented as:

\[ C \equiv C - C = O = O \]

This structure shows that there are multiple bonds between the carbon and oxygen atoms.

### Step 2: Count the Total Number of Covalent Bonds
In the structure \( C \equiv C - C = O = O \):
- The first carbon-carbon bond is a triple bond (1 sigma bond and 2 pi bonds).
- The second carbon-carbon bond is a single bond (1 sigma bond).
- The carbon-oxygen bonds are double bonds (1 sigma bond and 1 pi bond each).

Now, let's count the bonds:
- **C-C triple bond**: 1 sigma + 2 pi = 3 bonds
- **C-C single bond**: 1 sigma = 1 bond
- **C=O double bond (2 times)**: 2 sigma + 2 pi = 4 bonds

Adding these together:
- Total covalent bonds = 3 (from C-C) + 1 (from C-C) + 4 (from C=O) = 8 covalent bonds.

### Step 3: Count the Sigma and Pi Bonds
From the structure:
- **Total Sigma Bonds**:
- 1 from the triple bond (C-C)
- 1 from the single bond (C-C)
- 2 from the double bonds (C=O)

Total sigma bonds = 1 (from C≡C) + 1 (from C-C) + 2 (from C=O) = 4 sigma bonds.

- **Total Pi Bonds**:
- 2 from the triple bond (C-C)
- 1 from each double bond (C=O)

Total pi bonds = 2 (from C≡C) + 2 (from C=O) = 4 pi bonds.

### Final Answer
- Total number of covalent bonds in \( C_3O_2 \) is **8**.
- The total number of sigma bonds is **4** and the total number of pi bonds is **4**.