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The compound(s) with two lone pairs of e...

The compound(s) with two lone pairs of electron on the central atom is (are)

A

`BrF_(5)`

B

`ClF_(3)`

C

`XeF_(4)`

D

`SF_(4)`

Text Solution

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The correct Answer is:
To determine which compound(s) have two lone pairs of electrons on the central atom, we will analyze each compound step by step by calculating the total valence electrons and the number of bonds formed. ### Step 1: Analyze BrF5 1. **Determine the valence electrons**: Bromine (Br) has 7 valence electrons. 2. **Count the bonds**: In BrF5, bromine forms 5 single bonds with fluorine atoms. 3. **Calculate lone pairs**: - Total valence electrons = 7 - Electrons used in bonds = 5 (1 for each bond) - Remaining electrons = 7 - 5 = 2 electrons, which means there is 1 lone pair (2 electrons). ### Step 2: Analyze ClF3 1. **Determine the valence electrons**: Chlorine (Cl) also has 7 valence electrons. 2. **Count the bonds**: In ClF3, chlorine forms 3 single bonds with fluorine atoms. 3. **Calculate lone pairs**: - Total valence electrons = 7 - Electrons used in bonds = 3 - Remaining electrons = 7 - 3 = 4 electrons, which means there are 2 lone pairs (4 electrons). ### Step 3: Analyze XeF4 1. **Determine the valence electrons**: Xenon (Xe) has 8 valence electrons. 2. **Count the bonds**: In XeF4, xenon forms 4 single bonds with fluorine atoms. 3. **Calculate lone pairs**: - Total valence electrons = 8 - Electrons used in bonds = 4 - Remaining electrons = 8 - 4 = 4 electrons, which means there are 2 lone pairs (4 electrons). ### Step 4: Analyze SF4 1. **Determine the valence electrons**: Sulfur (S) has 6 valence electrons. 2. **Count the bonds**: In SF4, sulfur forms 4 single bonds with fluorine atoms. 3. **Calculate lone pairs**: - Total valence electrons = 6 - Electrons used in bonds = 4 - Remaining electrons = 6 - 4 = 2 electrons, which means there is 1 lone pair (2 electrons). ### Conclusion From the analysis: - BrF5 has 1 lone pair. - ClF3 has 2 lone pairs. - XeF4 has 2 lone pairs. - SF4 has 1 lone pair. Thus, the compounds with two lone pairs of electrons on the central atom are **ClF3 and XeF4**. ### Final Answer The compound(s) with two lone pairs of electrons on the central atom is (are) **ClF3 and XeF4**.

To determine which compound(s) have two lone pairs of electrons on the central atom, we will analyze each compound step by step by calculating the total valence electrons and the number of bonds formed. ### Step 1: Analyze BrF5 1. **Determine the valence electrons**: Bromine (Br) has 7 valence electrons. 2. **Count the bonds**: In BrF5, bromine forms 5 single bonds with fluorine atoms. 3. **Calculate lone pairs**: - Total valence electrons = 7 - Electrons used in bonds = 5 (1 for each bond) ...
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Knowledge Check

  • Which one of the following molecules contain one lone pair of electrons on the central atom?

    A
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    B
    `NH_3`
    C
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    D
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