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The sum of the number of lone pair of el...

The sum of the number of lone pair of electrons on each central atom in the following species is
`[TeBr_(6)]^(2-), [BrF_(2)]^(+), SNF_(3), and [XeF_(3)]^(-)`
(Atomic number : N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54)

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The correct Answer is:
To find the sum of the number of lone pairs of electrons on each central atom in the given species, we will analyze each species one by one. ### Step-by-Step Solution: 1. **Analyzing [TeBr₆]²⁻:** - Tellurium (Te) has 6 valence electrons. - In [TeBr₆]²⁻, Te is bonded to 6 bromine atoms. - Each bromine atom forms a single bond with Te, using 6 of Te's valence electrons. - The 2- charge means 2 additional electrons are added to Te. - Total electrons around Te = 6 (from bonds) + 2 (from charge) = 8 electrons. - Lone pairs on Te = (8 - 6) / 2 = 1 lone pair. 2. **Analyzing [BrF₂]⁺:** - Bromine (Br) has 7 valence electrons. - In [BrF₂]⁺, Br is bonded to 2 fluorine atoms. - Each fluorine forms a single bond with Br, using 2 of Br's valence electrons. - The +1 charge means 1 electron is removed from Br. - Total electrons around Br = 7 (valence) - 1 (due to charge) = 6 electrons. - Lone pairs on Br = (6 - 2) / 2 = 2 lone pairs. 3. **Analyzing SNF₃:** - Sulfur (S) has 6 valence electrons. - In SNF₃, S is bonded to 1 nitrogen and 3 fluorine atoms. - Total bonds = 1 (to N) + 3 (to F) = 4 bonds using 4 valence electrons. - Lone pairs on S = (6 - 4) / 2 = 1 lone pair. 4. **Analyzing [XeF₃]⁻:** - Xenon (Xe) has 8 valence electrons. - In [XeF₃]⁻, Xe is bonded to 3 fluorine atoms. - Total bonds = 3 (to F) using 3 valence electrons. - The -1 charge means 1 additional electron is added to Xe. - Total electrons around Xe = 8 (valence) + 1 (due to charge) = 9 electrons. - Lone pairs on Xe = (9 - 6) / 2 = 1.5 lone pairs, which means 3 lone pairs (since lone pairs are counted in whole numbers). 5. **Summing the Lone Pairs:** - Lone pairs from [TeBr₆]²⁻ = 1 - Lone pairs from [BrF₂]⁺ = 2 - Lone pairs from SNF₃ = 1 - Lone pairs from [XeF₃]⁻ = 3 - Total lone pairs = 1 + 2 + 1 + 3 = 7 lone pairs. ### Final Answer: The sum of the number of lone pairs of electrons on each central atom in the species is **7 lone pairs**.

To find the sum of the number of lone pairs of electrons on each central atom in the given species, we will analyze each species one by one. ### Step-by-Step Solution: 1. **Analyzing [TeBr₆]²⁻:** - Tellurium (Te) has 6 valence electrons. - In [TeBr₆]²⁻, Te is bonded to 6 bromine atoms. - Each bromine atom forms a single bond with Te, using 6 of Te's valence electrons. ...
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