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A conductor wire having 10^29 free elect...

A conductor wire having `10^29` free electrons `/ m^3` carries a current of 20A. If the cross-section of the wire is `1mm^2`, then the drift velocity of electrons will be :

A

`6.25 times 10^-3 ms^-1`

B

`1.25 times 10^-5 ms^-1`

C

`1.25 times 10^-3 ms^-1`

D

`1.25 times 10^-4 ms^-1`

Text Solution

AI Generated Solution

To find the drift velocity of electrons in a conductor wire, we can use the formula for current in terms of drift velocity: \[ I = n \cdot e \cdot A \cdot v_d \] Where: - \( I \) = current (in Amperes) - \( n \) = number of free electrons per unit volume (in electrons/m³) - \( e \) = charge of an electron (approximately \( 1.6 \times 10^{-19} \) Coulombs) ...
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