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A potential difference 100 V is applied ...

A potential difference 100 V is applied across a conductor which is a cylindrical shell of inner and outer diameter 2 cm and 4 cm respectively and length 10 cm. Current flows in a direction parallel to the axis of the conductor. If heat is dissipated in the conductor at the rate 15 W, the resistivity of the material of the conductor is _________ `Omega m`. [Take `pi=22/8`]

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To solve the problem, we need to find the resistivity of the material of the cylindrical conductor given the potential difference, dimensions of the conductor, and the rate of heat dissipation. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Potential difference (V) = 100 V - Inner diameter (d1) = 2 cm = 0.02 m - Outer diameter (d2) = 4 cm = 0.04 m ...
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