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Initial angular velocity of a circular d...

Initial angular velocity of a circular disc of mass `M` is `omega_(1)`. Then two small spheres of mass `m` are attached gently to two diametrically opposite points on the edge of the disc. What is the final angular velocity of the disc -

A

`((M+m)/M)omega_(1)`

B

`((M+m)/m)omega_(1)`

C

`(M/(M+4m))omega_(1)`

D

`(M/(M+2m))omega_(1)`

Text Solution

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The correct Answer is:
To solve the problem of finding the final angular velocity of a circular disc after two small spheres are attached to it, we will use the principle of conservation of angular momentum. ### Step-by-Step Solution: 1. **Identify Initial Conditions:** - The initial angular velocity of the disc is \( \omega_1 \). - The mass of the disc is \( M \). - The radius of the disc is \( R \). - The mass of each small sphere is \( m \). 2. **Calculate Initial Moment of Inertia:** - The moment of inertia \( I_1 \) of the disc about its center is given by: \[ I_1 = \frac{1}{2} M R^2 \] 3. **Determine the Moment of Inertia of the Spheres:** - When the two small spheres are attached to the disc, they are located at a distance \( R \) from the center. The moment of inertia \( I_2 \) for one sphere is: \[ I_2 = m R^2 \] - Since there are two spheres, the total moment of inertia contributed by the spheres is: \[ I_{spheres} = 2 \cdot m R^2 = 2m R^2 \] 4. **Calculate Total Moment of Inertia After Spheres are Added:** - The total moment of inertia \( I_{total} \) after adding the spheres is: \[ I_{total} = I_1 + I_{spheres} = \frac{1}{2} M R^2 + 2m R^2 \] 5. **Apply Conservation of Angular Momentum:** - According to the conservation of angular momentum: \[ I_1 \omega_1 = I_{total} \omega_{final} \] - Substituting the values we have: \[ \frac{1}{2} M R^2 \omega_1 = \left(\frac{1}{2} M R^2 + 2m R^2\right) \omega_{final} \] 6. **Solve for Final Angular Velocity \( \omega_{final} \):** - Rearranging the equation gives: \[ \omega_{final} = \frac{\frac{1}{2} M R^2 \omega_1}{\frac{1}{2} M R^2 + 2m R^2} \] - Simplifying this expression: \[ \omega_{final} = \frac{M \omega_1}{M + 4m} \] ### Final Answer: Thus, the final angular velocity of the disc after the two small spheres are attached is: \[ \omega_{final} = \frac{M}{M + 4m} \omega_1 \]

To solve the problem of finding the final angular velocity of a circular disc after two small spheres are attached to it, we will use the principle of conservation of angular momentum. ### Step-by-Step Solution: 1. **Identify Initial Conditions:** - The initial angular velocity of the disc is \( \omega_1 \). - The mass of the disc is \( M \). - The radius of the disc is \( R \). ...
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Knowledge Check

  • A thin circular ring of mass M and radius r is rotating about its axis with a constant angular velocity omega . Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring will now rotate with an angular velocity of

    A
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    B
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    C
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    B
    `(omega(M-2m))/(M+2m)`
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