Home
Class 12
CHEMISTRY
27 g of Al will react completely with…… ...

`27 g` of `Al` will react completely with…… `g` of `O_(2)`

Text Solution

Verified by Experts

`4Al + 3O_(2) rarr 2Al_(2)O_(3)`
Atomic weight of Al = 27
Thus `4 xx 27` of Al reacts with oxygen = `3 xx 32`g
27 g of Al reacts with oxygen = `3 xx 32 / 4 xx 27 xx 27 = 24 g`
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|21 Videos
  • STOICHIOMETRY - I

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos
  • STRUCTURE OF ATOM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|7 Videos

Similar Questions

Explore conceptually related problems

254 g of l_2 reacts completely with 142 g of Cl_2 to yield a mixture of ICI and ICI_3 . Ratio of moles of ICI and ICI_3 is

12 g of Mg (at. Mass 24) will react completely with acid to give

12 g of Mg (at. Mass 24) will react completely with acid to give

A is a binary compound of a univalent metal. When 1.422 g of A reacts completely with 0.321 g of sulphur in an evacuated and sealed tube, 1.743 g of white crystalline solid B produced, which produces a hydrated double salt C with Al_(2)(SO_(4))_(3) . Identfy A, B and C.

When 1 mole of PbS reacts completely with H_(2)O_(2)

Calculate the mass of aluminium oxide formed when 27 g of aluminium foil is burnt completely in oxygen. (Al= 27, O = 16)

80 g of H_(2) is reacted with 80 g of O_(2) to form water. Find out the mass of water obtained. Which substance is the limiting reagent ?

80 g of H_(2) is reacted with 80 g of O_(2) to form water. Find out the mass of water obtained. Which substance is the limiting reagent ?

6 g of H_(2) reacts with 14 g N_(2) to form NH_(3) till the reaction completely consumes the limiting reagent. The mass of other reactant (in g) left are ……

In the reaction: 2Al + Cr_(2) O_(3) rarr Al_(2) O_(3) + 2 Cr , 4.98 g of Al reacted with 20.0 g Cr_(2)O_(3) . How much grams of reactant ramains at the completion of the reaction?

VMC MODULES ENGLISH-STOICHIOMETRY-II-JEE Advanced (Archive)
  1. 27 g of Al will react completely with…… g of O(2)

    Text Solution

    |

  2. When the same amount of zinc is treated separately with excess of sulp...

    Text Solution

    |

  3. 5.5 g of a mixutre of FeSO4.7H2O and Fe2(SO4)3.9H2O requires 5.4 " mL ...

    Text Solution

    |

  4. If M is the molecular weight of KMnO(4), its equivalent weight will be...

    Text Solution

    |

  5. A 1.00 g sample of H(2)O(2) solution containing x percent H(2)O(2) by ...

    Text Solution

    |

  6. One mole of N(2)H(4) loses ten moles of electrons of form a new compou...

    Text Solution

    |

  7. Hydroxylamine reduce iron (III) according to the equation : 2NH(2)OH ...

    Text Solution

    |

  8. The oxidation number of carbon in CH2O is.

    Text Solution

    |

  9. The equivalent weight of MnSO(4) is half its molecular weight when it ...

    Text Solution

    |

  10. 2.68 xx 10^(-3) moles of a solution containing an ion A^(n+) require 1...

    Text Solution

    |

  11. The brown ring complex compound is formulated as [Fe(H(2)O)(5)NO]SO(4)...

    Text Solution

    |

  12. What is the weight of sodium bromate and molarity of solution to prepa...

    Text Solution

    |

  13. A sample of hydrazine sulphate (N2H6SO4) was dissolved in 100 " mL of ...

    Text Solution

    |

  14. The oxidation state of the mst electronegative element in the products...

    Text Solution

    |

  15. An equal volume of reducing agent is titrated separately with 1 M KMnO...

    Text Solution

    |

  16. A mixture of H(2)C(2)O(4) and NaHC(2)O(4) weighing 2.02 g was dissolve...

    Text Solution

    |

  17. The volume strength of 1.5 N H(2)O(2) solution is

    Text Solution

    |

  18. The oxidation number of phosphorus in Ba(H2 PO2)2 is :

    Text Solution

    |

  19. A solid mixture(5.000 g) consisting of lead nitrate and sodium nitrate...

    Text Solution

    |

  20. A solution of 0.2 g of a compound containing Cu^(2+) "and" C(2)O(4)^(2...

    Text Solution

    |