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The X and Y components of a force F acti...

The X and Y components of a force F acting at `30^(@)` to x-axis are respectively :

A

`(F)/(sqrt(2)), F`

B

`(F)/(2), (sqrt(3))/(2) F`

C

`(sqrt(3))/(2)F, (1)/(2)F`

D

`F,(F)/(sqrt(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the X and Y components of a force \( F \) acting at an angle of \( 30^\circ \) to the x-axis, we can follow these steps: ### Step 1: Understand the Force Components The force \( F \) can be resolved into two components: - The X component, which lies along the x-axis. - The Y component, which lies along the y-axis. ### Step 2: Use Trigonometric Functions The components can be calculated using trigonometric functions: - The X component is given by: \[ F_x = F \cos(30^\circ) \] - The Y component is given by: \[ F_y = F \sin(30^\circ) \] ### Step 3: Calculate the X Component Now, we need to calculate \( F_x \): - We know that \( \cos(30^\circ) = \frac{\sqrt{3}}{2} \). - Therefore, substituting this value, we get: \[ F_x = F \cos(30^\circ) = F \cdot \frac{\sqrt{3}}{2} = \frac{\sqrt{3}}{2} F \] ### Step 4: Calculate the Y Component Next, we calculate \( F_y \): - We know that \( \sin(30^\circ) = \frac{1}{2} \). - Therefore, substituting this value, we get: \[ F_y = F \sin(30^\circ) = F \cdot \frac{1}{2} = \frac{1}{2} F \] ### Step 5: Final Results Thus, the components of the force \( F \) acting at \( 30^\circ \) to the x-axis are: - X component: \( F_x = \frac{\sqrt{3}}{2} F \) - Y component: \( F_y = \frac{1}{2} F \) ### Conclusion The X and Y components of the force \( F \) are respectively \( \frac{\sqrt{3}}{2} F \) and \( \frac{1}{2} F \). ---
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