Among the following , the paramagnetic compound is :

Options

A. `Na_2O_2`
B. `O_3`
C. `N_2O`
D. `KO_2`

Answer

To determine which of the given compounds is paramagnetic, we need to analyze the total number of electrons in each compound. A compound is considered paramagnetic if it has an odd number of electrons, while it is diamagnetic if it has an even number of electrons (with the exception of certain cases where the total is 10 or 16, which are also paramagnetic).

Let's break down the solution step by step:

### Step 1: Analyze Na2O2
- Sodium (Na) has an atomic number of 11, which means it has 11 electrons.
- For Na2O2, we have:
- 2 Na: \(2 \times 11 = 22\) electrons
- Oxygen (O) has an atomic number of 8, so for 2 O: \(2 \times 8 = 16\) electrons
- Total electrons in Na2O2:
\[ 22 + 16 = 38 \text{ electrons} \]
- Since 38 is even, Na2O2 is diamagnetic.

### Step 2: Analyze O3
- Ozone (O3) consists of 3 oxygen atoms.
- Total electrons in O3:
- \(3 \times 8 = 24\) electrons
- Since 24 is even, O3 is also diamagnetic.

### Step 3: Analyze Na2O
- For Na2O, we have:
- 2 Na: \(2 \times 11 = 22\) electrons
- 1 O: \(1 \times 8 = 8\) electrons
- Total electrons in Na2O:
\[ 22 + 8 = 30 \text{ electrons} \]
- Since 30 is even, Na2O is diamagnetic.

### Step 4: Analyze K2O
- Potassium (K) has an atomic number of 19, so it has 19 electrons.
- For K2O, we have:
- 2 K: \(2 \times 19 = 38\) electrons
- 1 O: \(1 \times 8 = 8\) electrons
- Total electrons in K2O:
\[ 38 + 8 = 46 \text{ electrons} \]
- Since 46 is even, K2O is diamagnetic.

### Step 5: Identify the Paramagnetic Compound
- After analyzing all the compounds, we find that:
- Na2O2: 38 (diamagnetic)
- O3: 24 (diamagnetic)
- Na2O: 30 (diamagnetic)
- K2O: 46 (diamagnetic)

None of the compounds listed in the question are paramagnetic based on the analysis. However, if we consider the possibility of a different compound, we can conclude that if we had a compound with an odd number of electrons, it would be paramagnetic.

### Final Answer:
None of the provided options are paramagnetic based on the calculations.