The correct order regarding the electronegativity of hybrid orbitals of carbon is ?

Options

A. `sp gt sp^2 gt sp^3`
B. `sp lt sp^2 gt sp^3`
C. `sp lt sp^2 lt sp^3`
D. `sp gt sp^2 lt sp^3`.

Answer

To determine the correct order regarding the electronegativity of hybrid orbitals of carbon (sp, sp², and sp³), we can follow these steps:

### Step 1: Understand Hybridization
Hybridization is the mixing of atomic orbitals to form new hybrid orbitals. For carbon, the common types of hybridization are sp, sp², and sp³.

### Step 2: Identify the Percentage of s and p Character
- **sp Hybridization**: In sp hybridization, one s orbital and one p orbital combine to form two equivalent sp hybrid orbitals.
- Percentage s character = (1 s orbital / 2 total orbitals) × 100 = 50%
- Percentage p character = 100% - 50% = 50%

- **sp² Hybridization**: In sp² hybridization, one s orbital and two p orbitals combine to form three equivalent sp² hybrid orbitals.
- Percentage s character = (1 s orbital / 3 total orbitals) × 100 = 33.33%
- Percentage p character = 100% - 33.33% = 66.67%

- **sp³ Hybridization**: In sp³ hybridization, one s orbital and three p orbitals combine to form four equivalent sp³ hybrid orbitals.
- Percentage s character = (1 s orbital / 4 total orbitals) × 100 = 25%
- Percentage p character = 100% - 25% = 75%

### Step 3: Relate s Character to Electronegativity
Electronegativity is directly proportional to the percentage of s character in the hybrid orbitals. The more s character an orbital has, the higher its electronegativity.

### Step 4: Order the Hybrid Orbitals by Electronegativity
Based on the percentage of s character calculated:
- sp has 50% s character (highest electronegativity)
- sp² has 33.33% s character (medium electronegativity)
- sp³ has 25% s character (lowest electronegativity)

Thus, the order of electronegativity from highest to lowest is:
**sp > sp² > sp³**

### Step 5: Select the Correct Option
Now, we can look at the options provided in the question. The correct option will reflect the order we derived: sp > sp² > sp³.

### Final Answer
The correct order regarding the electronegativity of hybrid orbitals of carbon is:
**sp > sp² > sp³**

---