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The compressibility factor for H2 and He...

The compressibility factor for `H_2` and He is usually

A

gt1

B

`=1`

C

lt1

D

Either of these

Text Solution

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The correct Answer is:
To determine the compressibility factor for hydrogen (H₂) and helium (He), we need to understand the concept of the compressibility factor (Z) and how it relates to the behavior of gases. ### Step-by-Step Solution: 1. **Definition of Compressibility Factor (Z)**: The compressibility factor (Z) is defined as: \[ Z = \frac{PV}{RT} \] where: - \(P\) = pressure of the gas - \(V\) = volume of the gas - \(R\) = universal gas constant - \(T\) = temperature of the gas 2. **Ideal Gas Behavior**: For an ideal gas, the compressibility factor \(Z\) is equal to 1. This means that the gas behaves according to the ideal gas law without any deviations. 3. **Deviations from Ideal Behavior**: Real gases do not always behave ideally, especially under high pressure or low temperature. The compressibility factor can indicate whether a gas behaves more like an ideal gas or deviates from this behavior: - If \(Z < 1\), attractive forces dominate (the gas is more compressible). - If \(Z > 1\), repulsive forces dominate (the gas is less compressible). 4. **Behavior of Hydrogen (H₂) and Helium (He)**: Both hydrogen and helium are light gases with weak intermolecular forces. However, at certain conditions, particularly at higher pressures, the repulsive forces between gas molecules become significant. 5. **Conclusion on Compressibility Factor for H₂ and He**: For both hydrogen and helium, the repulsive forces dominate under typical conditions. Therefore, the compressibility factor \(Z\) for these gases is usually greater than 1: \[ Z > 1 \quad \text{for H₂ and He} \] ### Summary: The compressibility factor for hydrogen (H₂) and helium (He) is usually greater than 1, indicating that repulsive forces dominate in these gases.
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