Home
Class 12
CHEMISTRY
The formation of water from H(2)(g) and ...

The formation of water from `H_(2)(g)` and `O_(2)(g)` is an exothermic process because :

A

The chemical energy of `H_2(g) and O_(2)(g)` is mere than that of water

B

The chemical ener gy of `H_2(g) and O_(2)(g)` is less than that of water

C

The temperature of `H_2(g) and O_(2)(g)` is higher than that of water

D

The temperature of `H_2(g) and O_(2)(g)` is lower th an that of water

Text Solution

AI Generated Solution

The correct Answer is:
To determine why the formation of water from hydrogen gas (H₂) and oxygen gas (O₂) is an exothermic process, we can analyze the enthalpy change (ΔH) associated with the reaction. Here’s a step-by-step breakdown of the reasoning: ### Step 1: Understand the Reaction The chemical reaction for the formation of water can be written as: \[ 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \] This reaction involves the combination of hydrogen and oxygen gases to form liquid water. ### Step 2: Define Exothermic Reaction An exothermic reaction is one that releases heat to the surroundings. In terms of enthalpy change (ΔH), this means: \[ \Delta H < 0 \] This indicates that the energy of the products is less than the energy of the reactants. ### Step 3: Analyze Enthalpy Change Enthalpy (H) is a measure of the total energy of a thermodynamic system. The change in enthalpy (ΔH) during a reaction can be expressed as: \[ \Delta H = H_{\text{products}} - H_{\text{reactants}} \] For the reaction to be exothermic, the enthalpy of the products (water) must be lower than that of the reactants (hydrogen and oxygen). ### Step 4: Compare Energies In this case, the chemical energy stored in the bonds of hydrogen (H₂) and oxygen (O₂) is greater than that stored in the bonds of water (H₂O). Therefore: \[ H_{\text{reactants}} > H_{\text{products}} \] This means that when hydrogen and oxygen combine to form water, some of the stored energy in the reactants is released as heat, resulting in a negative ΔH. ### Step 5: Conclusion Thus, the formation of water from hydrogen and oxygen is an exothermic process because the chemical energy of the reactants (H₂ and O₂) is greater than that of the product (H₂O). This results in a release of energy, making ΔH negative. ### Final Answer The formation of water from H₂ and O₂ is an exothermic process because the chemical energy of H₂ and O₂ is greater than that of water. ---
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Enable|49 Videos
  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Efficient|48 Videos
  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|44 Videos

Similar Questions

Explore conceptually related problems

For the process, H_(2)O(l) to H_(2)O(g)

The formation of the oxide ion O_(g)^(2-) requires first an exothermic and then an endothermic step as shown below: O_(g)+e^(-) rarr O_(g)^(-) , DeltaH=-142 kJ mol^(-1) O(g)+e rarr O_(g)^(2-) , DeltaH=844kJ mol^(-1) This is because:

Knowledge Check

  • The formation of the oxide ion O^(2-) (g) requires first an exothermic and then an endothermic step as shown below : O (g) + e^(-)= O^(-) (g), DeltaH^(@) = - 142 kJ moI^(-1) O(g)+e^(-)toO^(2-)(g),DeltaH^(@)=844kJmol^(-1) This is because

    A
    oxygen is more electronegative
    B
    oxygen has high electron affinity
    C
    `O^(-)` ion will tend to resist the addition of another electron
    D
    `O^(-)` ion has comparatively larger size than oxygen atom.
  • Similar Questions

    Explore conceptually related problems

    The value of DeltaH_(O-H) is 109 kcal mol^(-1) . Then formation of one mole of water in gaseous state from H(g) and O(g) is accompanied by

    The reaction 2NO_(2)(g) hArr N_(2)O_(4)(g) is an exothermic equilibrium . This means that:

    The reactions between H_(2)(g) and O_(2)(g) is highly feasuble yet allowing the gases to stand at room tempertaure in the same vessel does not lead to the formation of water . Explain

    Assertion: The formation of F_((g))^(-) from F_((g)) is exothermic, whereas that of O_((g))^(2-) from O_((g)) is endotherrmic. Reason: The addition of second electron to a monovalent anion is difficult because both have the same charge and experience more repulsion.

    The formation of oxide ion O^(2-)(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below O(g)+e^(-) rarr O^(-)(g), DeltaH^(-) = - 141 kj mol^(-1) O^(-)(g) +e^(-) rarr O^(2-) (g), DeltaH^(-) =+ 780 kj mol^(-1) Thus, process of formation of O^(2-) in gas phase is unfavourable even through O^(2-) is isoelectronic with neon. It is due to the fact that m

    Assertion: pH of water increases on increasing temperature. Reason: H_(2)O rarr H^(+) + OH^(-) is an exothermic process.

    The volume of O_(2) liberated from 0.96g of H_(2)O_(2) is