Home
Class 12
CHEMISTRY
For the reversible reaction. A(s)+B(g)...

For the reversible reaction.
`A(s)+B(g) Leftrightarrow C(g)+D(g), triangleG^(@)=-350kJ`
Which one of the following statement is true?

A

The reaction is thermodynamically non-feasible

B

the entropy change is negative

C

Equilibrium constant is greater than one

D

The reaction should be instantaneous

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is true regarding the reversible reaction \( A(s) + B(g) \leftrightarrow C(g) + D(g) \) with a given \( \Delta G^\circ = -350 \, \text{kJ} \), we will analyze the implications of the negative Gibbs free energy change and the characteristics of the reaction. ### Step-by-Step Solution: 1. **Understanding Gibbs Free Energy (\( \Delta G^\circ \))**: - The Gibbs free energy change (\( \Delta G^\circ \)) indicates the spontaneity of a reaction. A negative \( \Delta G^\circ \) suggests that the reaction is spontaneous under standard conditions. 2. **Evaluating the First Statement**: - The first statement claims that the reaction is thermodynamically non-feasible or non-spontaneous. Since \( \Delta G^\circ \) is negative (-350 kJ), this statement is **incorrect**. 3. **Evaluating the Second Statement**: - The second statement asserts that the entropy change is negative. To evaluate this, we calculate the change in the number of moles of gas (\( \Delta n_g \)): - Products: \( C(g) + D(g) \) = 2 moles of gas - Reactants: \( B(g) \) = 1 mole of gas - Therefore, \( \Delta n_g = 2 - 1 = 1 \) (which is positive). - A positive \( \Delta n_g \) indicates an increase in entropy, making this statement **incorrect**. 4. **Evaluating the Third Statement**: - The third statement claims that the equilibrium constant \( K \) is greater than 1. The relationship between \( \Delta G^\circ \) and the equilibrium constant is given by: \[ \Delta G^\circ = -2.303RT \log K \] - Since \( \Delta G^\circ \) is negative, this implies that \( \log K \) must be positive, which means \( K > 1 \). Thus, this statement is **correct**. 5. **Evaluating the Fourth Statement**: - The fourth statement suggests that the reaction would be instantaneous. However, the speed of a reaction (kinetics) is independent of the Gibbs free energy change. Therefore, this statement is **incorrect**. ### Conclusion: The only true statement among the options provided is that the equilibrium constant is greater than 1.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Efficient|48 Videos
  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|44 Videos

Similar Questions

Explore conceptually related problems

In the reversible reaction, 2HI(g) hArr H_(2)(g)+I_(2)(g), K_(p) is

For the given reaction 2A(g)+ B(g) hArr C(g) , Delta H = x kJ which of the following favour the reactants ?

Consider the following reversible reactionat equilibrium: 2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g), DeltaH=+24.7 kJ Which one of the following changes in conditions will lead to maximum decomposition of H_(2)O(g) ?

The graph of g(x) is shown in the figure above. If h(x)=-g(x)+1 , which of the following statements is true?

For the reaction CH_(4(g))+2O_(2(g))hArrCO_(2(g))+2H_(2)O_(l) : ( DeltaH=-170.8 kJmol^(-1) ). Which of the following statement is not true?

The K_c for given reaction will be A_2 (g) +2B (g) hArr C(g) +2D(s)

Given a gas phase reaction 2A(g)+B(g)hArr C(g)+D(g) . Which one of the following changes will affect the value of K_(c) ?

For the reaction: 2A(g)+B(g) hArr 3C(g)+D(g) Two moles each of A and B were taken into a flask. The following must always be true when the system attained equilibrium

For the reaction C_(2)H_(4)(g) + H_(2)(g) rarr C_(2)H_(6)(g) , which of the following expressions between K_(p) "and" K_(c) is true at 27^(@)C ?

For the reaction Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g) , which one of the following is true :