The hydrolysis of sodium carbonate involves

Options

A. Reaction between `Na^(+)` and water
B. Reaction between `Na^(+)` and `H^(+)`
C. Reaction between `CO_(3)^(2-)` and water
D. Reaction between `CO_(3)^(-2)` and `H^(+)`

Answer

To solve the question regarding the hydrolysis of sodium carbonate (Na2CO3), we will break down the process step by step.

### Step-by-Step Solution:

1. **Understanding Hydrolysis**: Hydrolysis is a chemical reaction involving the breaking down of a compound when it reacts with water. In the case of sodium carbonate, we need to identify how it interacts with water.

2. **Identifying Components**: Sodium carbonate (Na2CO3) consists of sodium ions (Na+) and carbonate ions (CO3^2-). When dissolved in water, it dissociates into these ions:
\[ \text{Na}_2\text{CO}_3 \rightarrow 2 \text{Na}^+ + \text{CO}_3^{2-} \]

3. **Reaction of Carbonate Ion with Water**: The carbonate ion (CO3^2-) can react with water (H2O) to undergo hydrolysis. The reaction can be represented as:
\[ \text{CO}_3^{2-} + \text{H}_2\text{O} \rightleftharpoons \text{HCO}_3^{-} + \text{OH}^- \]
In this reaction, the carbonate ion accepts a proton (H+) from water, forming bicarbonate (HCO3^-) and hydroxide ions (OH^-).

4. **Resulting Products**: The products of this hydrolysis reaction are bicarbonate ions (HCO3^-) and hydroxide ions (OH^-). The formation of hydroxide ions indicates that the solution will be basic.

5. **Conclusion**: Therefore, the hydrolysis of sodium carbonate primarily involves the reaction between the carbonate ion (CO3^2-) and water (H2O).

### Final Answer:
The hydrolysis of sodium carbonate involves the reaction between carbonate ions and water. Hence, the correct option is:
**C. Reaction between CO3^2- and water.**

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