Methy`-`tert-buty`-ether` on heating with `HI` of one molar concentration gives

Options

A. `CH_(3) I + (CH_(3))_(3) COH`
B. `CH_(3) OH + (CH_(3)) _(3) Cl`
C. `CH_(3) I + (CH_(3))_(3) CI`
D. None of the above

Answer

To solve the problem of what methyl tert-butyl ether gives when heated with HI of one molar concentration, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Methyl Tert-Butyl Ether**:
- The structure of methyl tert-butyl ether can be represented as:
\[ \text{CH}_3\text{-O-}\text{C}(\text{CH}_3)_3 \]
- This means it has a methyl group (CH3) attached to an oxygen (O), which is then attached to a tert-butyl group (C(CH3)3).

2. **Reaction with HI**:
- When methyl tert-butyl ether is heated with HI, the ether undergoes cleavage. HI is a strong acid and can protonate the ether oxygen.
- The oxygen atom in the ether has lone pairs and can accept a proton (H+) from HI, leading to the formation of an oxonium ion:
\[ \text{CH}_3\text{-O}^+\text{-C}(\text{CH}_3)_3 \]

3. **Formation of Carbocation**:
- The protonated ether can then lead to the formation of a carbocation. The bond between the oxygen and the tert-butyl group will break, resulting in a tert-butyl carbocation and methanol:
\[ \text{CH}_3\text{-OH} + \text{C}(\text{CH}_3)_3^+ \]

4. **Nucleophilic Attack by Iodide Ion**:
- The iodide ion (I-) from HI can now attack the carbocation formed. This leads to the formation of tert-butyl iodide:
\[ \text{C}(\text{CH}_3)_3\text{-I} \]

5. **Final Products**:
- The final products of the reaction are:
- Methanol (CH3OH)
- Tert-butyl iodide (C(CH3)3I)

### Conclusion:
When methyl tert-butyl ether is heated with 1 M HI, it produces methanol and tert-butyl iodide.