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Phenol and benzoic acid may be distingui...

Phenol and benzoic acid may be distinguished by their reaction with :

A

NaOH

B

`Na HCO_(3)`

C

`Na_(2) CO_(3)`

D

`H_(2) SO_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To distinguish between phenol and benzoic acid, we can analyze their reactions with various reagents. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Structures - **Phenol** has the structure: C6H5OH (a hydroxyl group attached to a benzene ring). - **Benzoic Acid** has the structure: C6H5COOH (a carboxylic acid group attached to a benzene ring). ### Step 2: Identify the Acidity - Both phenol and benzoic acid are acidic, but benzoic acid is a stronger acid than phenol. - **Phenol** is a weak acid, while **benzoic acid** is a stronger acid due to the stability of its conjugate base (benzoate ion) through resonance. ### Step 3: Analyze the Reactions with Sodium Hydroxide (NaOH) - When phenol reacts with NaOH, it forms sodium phenoxide: \[ \text{C6H5OH} + \text{NaOH} \rightarrow \text{C6H5O}^- \text{Na}^+ + \text{H2O} \] - When benzoic acid reacts with NaOH, it forms sodium benzoate: \[ \text{C6H5COOH} + \text{NaOH} \rightarrow \text{C6H5COO}^- \text{Na}^+ + \text{H2O} \] - **Conclusion**: Both phenol and benzoic acid react with NaOH to form soluble salts, so NaOH cannot distinguish between them. ### Step 4: Analyze the Reactions with Sodium Bicarbonate (NaHCO3) - **Phenol** does not react with NaHCO3, and no effervescence occurs. - **Benzoic Acid** reacts with NaHCO3, producing sodium benzoate and releasing carbon dioxide (effervescence): \[ \text{C6H5COOH} + \text{NaHCO3} \rightarrow \text{C6H5COO}^- \text{Na}^+ + \text{H2O} + \text{CO2} \uparrow \] - **Conclusion**: The effervescence of CO2 when reacting with benzoic acid allows us to distinguish it from phenol. ### Step 5: Analyze the Reactions with Sodium Carbonate (Na2CO3) - Similar to NaHCO3, phenol does not react with Na2CO3, resulting in no effervescence. - Benzoic acid will react with Na2CO3, producing sodium benzoate and releasing CO2, albeit more slowly than with NaHCO3: \[ \text{C6H5COOH} + \text{Na2CO3} \rightarrow \text{C6H5COO}^- \text{Na}^+ + \text{H2O} + \text{CO2} \uparrow \] - **Conclusion**: Na2CO3 can also distinguish between phenol and benzoic acid due to the release of CO2. ### Step 6: Analyze the Reaction with Sulfuric Acid (H2SO4) - Both phenol and benzoic acid undergo sulfonation when treated with H2SO4, but this does not lead to a clear distinction: - Phenol reacts to form ortho and para sulfonated products. - Benzoic acid reacts to form a meta sulfonated product. - **Conclusion**: The sulfonation does not provide a clear distinction in a practical sense, as both products will still be soluble. ### Final Conclusion The reagents that can be used to distinguish between phenol and benzoic acid are: - **Sodium Bicarbonate (NaHCO3)**: Produces effervescence with benzoic acid but not with phenol. - **Sodium Carbonate (Na2CO3)**: Also produces effervescence with benzoic acid but at a slower rate. Thus, the correct answer is **B (NaHCO3)** and **C (Na2CO3)**. ---
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Phenol and carboxylic acid can be distinguished by

Statement -1 : Phenol and benzoic acid can be distinguished by NaHCO_(3) Statement -2 Phenol releases CO_(2) gas from NaHCO_(3)

Knowledge Check

  • Phenol and benzoic acid can be distinguished by :

    A
    aqueous `NaHCO_(3)`
    B
    aqueous `NaNO_(3)`
    C
    aqueous NaOH
    D
    conc. `H_(2)SO_(4)`
  • Assertion : Phenol and benzoic acid can be distinguished by Na_(2)CO_(3). Reason : Benzoic acid is stronger acid than phenol, hence reacts with Na_(2)CO_(3) .

    A
    If both assertion and reason are true and reason is the correct explanation of assertion.
    B
    If both assertion and reason are true but reason is not the correct explanation of assertion.
    C
    If assertion is true but reason is false.
    D
    If both assertion and reason are false.
  • The conversion of acetophenone into benzoic acid can be achieved by its reaction with :

    A
    sodium hydroxide followed by acidification
    B
    iodine and sodium hydroxide, followed by acidification
    C
    hydroxylamine followed by reaction with `H_(2)SO_(4)`
    D
    m-chloroperoxobenzoic acid
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