Write down the hybridization of central atom and shape of `XeF_(2).`

Explanation

To determine the hybridization of the central atom and the shape of the molecule \( \text{XeF}_2 \), we can follow these steps:

### Step 1: Identify the central atom and its valence electrons
The central atom in \( \text{XeF}_2 \) is xenon (Xe). Xenon is a noble gas and is in Group 18 of the periodic table. It has a complete octet, meaning it has 8 valence electrons.

### Step 2: Determine the number of bonds and lone pairs
In \( \text{XeF}_2 \), xenon forms two bonds with two fluorine atoms. Each fluorine atom contributes one electron to form a single bond with xenon. Therefore, there are 2 sigma bonds.

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