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A molecule XY2 contains two sigma, two p...

A molecule `XY_2` contains two `sigma`, two `pi` and one lone pair of electron in valence shell of X. The arrangement of lone pair as well as bond pairs is

A

square pyramidal

B

linear

C

trigonal planar

D

unpredictable

Text Solution

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The correct Answer is:
To determine the arrangement of lone pairs and bond pairs in the molecule `XY2`, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Number of Electrons:** - The molecule `XY2` has 2 sigma bonds, 2 pi bonds, and 1 lone pair of electrons in the valence shell of atom X. - Each sigma bond is formed by 2 electrons, and each pi bond is formed by 2 electrons as well. - Therefore, the total number of electrons involved is: - 2 (from sigma bonds) + 2 (from pi bonds) + 1 (from the lone pair) = 5 electrons. 2. **Determine the Group of Element X:** - Since the total number of valence electrons is 6, element X must belong to group 16 of the periodic table (which includes elements like oxygen, sulfur, etc.). 3. **Analyze the Structure:** - A common example of a molecule with this configuration is sulfur dioxide (SO2). - In SO2, sulfur (S) is the central atom (X), bonded to two oxygen atoms (Y). - The structure can be visualized as: - S has 2 sigma bonds with O and 2 pi bonds (one for each O), and 1 lone pair. 4. **Determine Hybridization:** - The steric number is calculated as the sum of sigma bonds and lone pairs: - Steric number = Number of sigma bonds + Number of lone pairs = 2 + 1 = 3. - This indicates that the hybridization of X is sp². 5. **Determine Molecular Geometry:** - With a steric number of 3 and one lone pair, the molecular geometry is trigonal planar. - However, due to the presence of the lone pair, the actual shape becomes bent (or V-shaped). 6. **Conclusion:** - The arrangement of lone pairs and bond pairs in the molecule `XY2` is such that it has a bent shape due to the repulsion between the lone pair and the bonding pairs. ### Final Answer: The arrangement of lone pairs and bond pairs in the molecule `XY2` is a bent shape due to the presence of one lone pair and two bond pairs.

To determine the arrangement of lone pairs and bond pairs in the molecule `XY2`, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Number of Electrons:** - The molecule `XY2` has 2 sigma bonds, 2 pi bonds, and 1 lone pair of electrons in the valence shell of atom X. - Each sigma bond is formed by 2 electrons, and each pi bond is formed by 2 electrons as well. - Therefore, the total number of electrons involved is: ...
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A molecule XY_(2) contains two sigma bonds two pi bond and one lone pair of electrons in the valence shell of X . The arrangement of lone pair as well as bond pairs is

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Knowledge Check

  • The total number of lone pairs of electrons in melamine is

    A
    12
    B
    8
    C
    10
    D
    6
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