As the s-character of hybridisation orbital increase, the bond angle

Options

A. Increase
B. Decreases
C. Becomes zero
D. Does not change

Answer

To solve the question, "As the s-character of hybridization orbital increases, the bond angle...", we can follow these steps:

### Step 1: Understand Hybridization
Hybridization is the concept used to explain the shape of molecules. It involves the mixing of atomic orbitals to form new hybrid orbitals that can form bonds.

### Step 2: Identify the Types of Hybridization
The common types of hybridization are:
- **sp³ hybridization**: 25% s-character, 75% p-character
- **sp² hybridization**: 33.33% s-character, 66.67% p-character
- **sp hybridization**: 50% s-character, 50% p-character

### Step 3: Analyze Bond Angles
The bond angles associated with these hybridizations are:
- **sp³**: 109.5 degrees
- **sp²**: 120 degrees
- **sp**: 180 degrees

### Step 4: Observe the Trend
As we move from sp³ to sp² to sp hybridization, the s-character increases:
- sp³ (25% s-character) has a bond angle of 109.5 degrees.
- sp² (33.33% s-character) has a bond angle of 120 degrees.
- sp (50% s-character) has a bond angle of 180 degrees.

### Step 5: Conclusion
From the analysis, we can conclude that as the s-character of hybridization increases, the bond angle also increases.

### Final Answer
Therefore, the correct answer to the question is that as the s-character of hybridization increases, the bond angle **increases**.

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