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In a spontaneous reaction, the free ener...

In a spontaneous reaction, the free energy of a system :

A

Positive

B

Negative

C

Zero

D

Can be positive or negative

Text Solution

Verified by Experts

The correct Answer is:
B
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A: A non- spontaneous process becomes spontaneous when coupled with a suitable spontaneous reaction. R: The overall free energy of coupled spontaneous reaction is negative.

The change in Gibbs free energy of the system along provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a sytem at constant temperature and pressure will be: DeltaG_("system") = DeltaH_("system") - T DeltaS_("system") For a spontaneous reaction DeltaG , equilibrium constant K and E_("cell")^(0) will be respectively:

The change in Gibbs free energy of the system along provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a sytem at constant temperature and pressure will be: DeltaG_("system") = DeltaH_("system") - T DeltaS_("system") The free energy for a reaction having Delta H= 31400 cal, DeltaS= 32 cal K^(-1) mol^(-1) at 1000^(@)C is

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A chemical process always proceeds in the direction in which the Gibbs free energy of the system decreases.

Assertion (A): The thermodynamic factor which determines the spontaneity of a process is the free energy. For a process to be spontaneous the free energy must be-ve. Reason (R ) : The change in free energy is related to the change in a process must always be positive if its is spontaneous.

A change in the free energy of a system at constant temperature and pressure will be: Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S At constant temperature and pressure Delta_(sys) G lt 0 (spontaneous) Delta_(sys)G = 0 (equilibrium) Delta_(sys)G gt 0 (non-spontaneous) The free enegry for a reaction having DeltaH = 31400 cal, DeltaS = 32 cal K^(-1) mol^(-1) at 1000^(@)C is

A change in the free energy of a system at constant temperature and pressure will be: Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S At constant temperature and pressure Delta_(sys) G lt 0 (spontaneous) Delta_(sys)G = 0 (equilibrium) Delta_(sys)G gt 0 (non-spontaneous) If both DeltaH and Deltas are negative, the reaction will be spontaneous

A change in the free energy of a system at constant temperature and pressure will be: Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S At constant temperature and pressure Delta_(sys) G lt 0 (spontaneous) Delta_(sys)G = 0 (equilibrium) Delta_(sys)G gt 0 (non-spontaneous) For a spontaneous reaction DeltaG , equilibrium K and E_(cell)^(Theta) will be, respectively

Assertion :- Entropy of system increases for a spontaneous reactions. Reason :- Enthalpy of reaction always decreases for spontaneous reaction.