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The bond dissociation energies of X2, Y2...

The bond dissociation energies of `X_2, Y_2 and XY` are in the ratio of `1 : 0.5 : 1. DeltaH` for the formation of XY is -200 kJ mol^(-1)`. The bond dissociation energy of `X_2` will be

A

`"100 kJ mole"^(-1)`

B

`"800 kJ mole"^(-1)`

C

`"300 kJ mole"^(-1)`

D

`"400 kJ mole"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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If the bond dissociation energies of XY , X_(2) and Y_(2) are in the ratio of 1:1:0.5 and DeltaH_(f) for the formation of Xy is -200 KJ//mol . The bond dissociation energy of X_(2) will be :-

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Knowledge Check

  • Enthalpy change for the reaction, 4H(g) to 2H_2(g) is -869.6 kJ The dissociation energy of H - H bond is

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