The statement "If 0.003 moles of a gas are dissolved in 900 g of water under a pressure of 1 atmosphere , 0.006 moles will be dissolved under a pressure of 2 atmosphere " illustrates

Options

A. Dalton's Law of partial pressures
B. Graham's law
C. Raoult's law
D. Henry's law

Answer

To solve the question, we need to analyze the statement provided and identify which law it illustrates. Here’s a step-by-step breakdown:

### Step 1: Understand the Statement
The statement mentions that 0.003 moles of a gas are dissolved in 900 g of water under a pressure of 1 atmosphere, and that 0.006 moles will dissolve under a pressure of 2 atmospheres.

### Step 2: Identify the Relationship
From the information given, we can see that the amount of gas dissolved is directly proportional to the pressure applied. When the pressure increased from 1 atm to 2 atm, the amount of gas dissolved increased from 0.003 moles to 0.006 moles.

### Step 3: Relate to Gas Laws
The relationship observed here is consistent with Henry's Law, which states that the amount of gas that dissolves in a liquid is directly proportional to the partial pressure of that gas above the liquid.

### Step 4: Evaluate the Options
Now, let's analyze the options provided:
- **Option A: Dalton's Law of Partial Pressure** - This law deals with the total pressure of a mixture of gases and is not relevant here.
- **Option B: Graham's Law** - This law relates to the rates of effusion and diffusion of gases and is not applicable.
- **Option C: Raoult's Law** - This law pertains to the vapor pressure of solutions and does not apply to gas solubility in liquids.
- **Option D: Henry's Law** - This law directly relates to the solubility of gases in liquids and is applicable here.

### Conclusion
The correct answer is **Option D: Henry's Law**, as it accurately describes the relationship between the pressure of a gas and its solubility in a liquid.

---