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Identify the reactant X and the product ...

Identify the reactant X and the product Y
`CH_(3) - CO - CH_(3) + X rarr (CH_(3))_(3) C - OMg - Cl rarr Hydrolysis`
`Y + Mg (OH) CI`

A

`X = MgCl_(2) , Y = CH_(3) -CH=CH_(2)`

B

`X= CH_(3)MgCl, Y = C_(2)H_(5)COCH_(3)`

C

`X=CH_(3)MgCl,Y= (CH_(3))_(3)C-OH`

D

`X=C_(2)H_(5)MgCl, Y = (CH_(3))_(3)C-OH`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the reactant X and the product Y in the given reaction sequence. The reaction involves acetone (CH₃COCH₃) reacting with a reactant X to form an intermediate, which upon hydrolysis yields product Y and Mg(OH)Cl. ### Step-by-Step Solution: 1. **Identify the Reactant**: - The starting compound is acetone (CH₃COCH₃). - The reactant X is a Grignard reagent. Grignard reagents are typically of the form R-Mg-X, where R is an alkyl or aryl group and X is a halogen. - In this case, we need a Grignard reagent that can react with the carbonyl group of acetone. The most suitable Grignard reagent is methyl magnesium chloride (CH₃MgCl). 2. **Reaction with Grignard Reagent**: - When acetone reacts with methyl magnesium chloride, the nucleophilic methyl group (CH₃⁻) attacks the electrophilic carbon of the carbonyl group (C=O) in acetone. - This results in the formation of a tetrahedral intermediate where the oxygen becomes negatively charged. 3. **Formation of the Intermediate**: - The negatively charged oxygen then coordinates with the magnesium ion (Mg²⁺) from the Grignard reagent, forming a complex. - The structure of the intermediate can be represented as CH₃C(OH)(CH₃)MgCl, which is a magnesium alkoxide. 4. **Hydrolysis**: - Upon hydrolysis, the intermediate reacts with water (or another source of protons) to replace the MgCl group with a hydrogen atom. - This results in the formation of a tertiary alcohol. 5. **Identify the Product Y**: - The product formed after hydrolysis is 2-methyl-2-propanol (also known as tert-butanol), which can be represented as (CH₃)₃COH. - Therefore, the product Y is 2-methyl-2-propanol. ### Final Identification: - **Reactant X**: Methyl magnesium chloride (CH₃MgCl) - **Product Y**: 2-methyl-2-propanol ((CH₃)₃COH) ### Summary: - The reactant X is CH₃MgCl (methyl magnesium chloride). - The product Y is (CH₃)₃COH (2-methyl-2-propanol).
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Knowledge Check

  • Conversion (CH_3 - CH_3 rarr CH_3 - CH_2 - OH) " alkane " rarr alcohol is ahieved by :

    A
    `Br_2//hv, alc KOH`
    B
    `Br_2 //hv, aq. KOH`
    C
    `Br_2//C Cl_4, LiAlH_4`
    D
    `Br_2//C Cl_4, NaBH_4`
  • Identify the products X and Y formed in the following reaction. CH_3-CH_2-CH=CH-CH_3+HCl = X+Y

    A
    a. `X=CH_3CH_2CH_2CH_2CH_2Cl`,
    `Y=CH_3CH_2-underset(Cl)underset(|)(CH)-CH_2CH_3`
    B
    b. `X=CH_3CH_2-underset(Cl)underset(|)(CH)-CH_2CH_3, Y=CH_3CH_2CH_2-underset(Cl)underset(|)(CH)-CH_3`
    C
    c.`X=CH_3CH_2-underset(Cl)underset(|)(CH)-CH_2CH_3, Y=CH_3-underset(Cl)underset(|)(CH)-underset(Cl)underset(|)(CH)-CH_2CH_3`
    D
    d.`X=ClCH_2-CH_2-CH=CH-CH_3, Y=CH_3CH_2-CH=CH-CH_2Cl`
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