Glucose + Tollen's reagent `to` silver mirror. The process shows:

Options

A. Presence of acidic group
B. Presence of alkaline group
C. Presence of ketonic group
D. Presence of aldehyde group

Answer

To solve the question regarding the reaction of glucose with Tollen's reagent and the formation of a silver mirror, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this case is glucose, which is a simple sugar (monosaccharide).

2. **Understand Tollen's Reagent**:
- Tollen's reagent is a solution of silver nitrate (AgNO3) in ammonia (NH3). It is used to test for the presence of aldehyde groups in compounds.

3. **Structure of Glucose**:
- The molecular structure of glucose can be represented as:
\[ \text{C}_6\text{H}_{12}\text{O}_6 \]
- In its open-chain form, glucose has an aldehyde group (-CHO) at one end of the molecule.

4. **Reaction with Tollen's Reagent**:
- When glucose (which contains an aldehyde group) reacts with Tollen's reagent, the aldehyde group is oxidized to a carboxylic acid group, forming gluconic acid.
- The reaction can be summarized as:
\[ \text{Glucose} + \text{Tollen's reagent} \rightarrow \text{Gluconic acid} + \text{Ag (s)} \text{ (silver mirror)} \]

5. **Formation of Silver Mirror**:
- The reduction of silver ions (Ag+) to metallic silver (Ag) results in the formation of a silver mirror on the surface of the reaction vessel.

6. **Conclusion**:
- The formation of a silver mirror indicates the presence of an aldehyde group in glucose. Therefore, the process shows the presence of an aldehyde group.

### Final Answer:
The process shows the presence of an aldehyde group in glucose.