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The potential difference applied to an X - ray tube is 5 KV and the current through it is 3.2 m A. Then the number of electron striking the target per second is .

A

`2xx10^(16)`

B

`5xx10^(6)`

C

`1xx10^(17)`

D

`4xx10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
I=`(q)/(t)`=`("ne")/(t)` `rArr` n=`(it)/(e)`=`(3.2xx10^(-3)xx1)/(1.6xx10^(-19))`=`2xx10^(16)`
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