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The relation between voltage sensitivity...

The relation between voltage sensitivity ` 'sigma_(V)'` and current sensitiviy `sigma_(i)` of moving coil galvanometer if its resistance is `'G'` is

A

`sigma_(i)/G=sigma_(v)`

B

`sigma_(v)/G=sigma_(i)`

C

`G/sigma_(v)=sigma_(i)`

D

`G/sigma_(i)/G=sigma_(v)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the relation between voltage sensitivity \( \sigma_V \) and current sensitivity \( \sigma_I \) of a moving coil galvanometer with resistance \( G \), we can follow these steps: ### Step 1: Define Current Sensitivity Current sensitivity \( \sigma_I \) is defined as the deflection produced per unit current. Mathematically, it can be expressed as: \[ \sigma_I = \frac{\phi}{I} \] where \( \phi \) is the deflection and \( I \) is the current. ### Step 2: Express Current Sensitivity in Terms of Physical Quantities For a moving coil galvanometer, the current sensitivity can be expressed in terms of the number of turns \( n \), magnetic field \( B \), area \( A \), and the torsional constant \( C \): \[ \sigma_I = \frac{nBA}{C} \] ### Step 3: Define Voltage Sensitivity Voltage sensitivity \( \sigma_V \) is defined as the deflection produced per unit voltage applied across the galvanometer. This can be expressed as: \[ \sigma_V = \frac{\phi}{V} \] where \( V \) is the voltage. ### Step 4: Relate Voltage to Current Using Ohm's law, the voltage \( V \) across the galvanometer can be expressed in terms of current \( I \) and resistance \( G \): \[ V = I \cdot G \] ### Step 5: Substitute Voltage in Voltage Sensitivity Substituting \( V \) in the expression for voltage sensitivity: \[ \sigma_V = \frac{\phi}{I \cdot G} \] ### Step 6: Express Voltage Sensitivity in Terms of Physical Quantities We can express \( \phi \) in terms of the same physical quantities used for current sensitivity: \[ \sigma_V = \frac{nBA}{C \cdot G} \] ### Step 7: Relate \( \sigma_V \) and \( \sigma_I \) Now, we can relate \( \sigma_V \) and \( \sigma_I \): \[ \sigma_V = \frac{nBA}{C \cdot G} = \frac{\sigma_I}{G} \] ### Conclusion Thus, the relation between voltage sensitivity \( \sigma_V \) and current sensitivity \( \sigma_I \) is: \[ \sigma_V = \frac{\sigma_I}{G} \]
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