Predict the block, period and group to which tin belongs.

Answer

To determine the block, period, and group to which tin (Sn) belongs, we can follow these steps:

### Step 1: Identify the Atomic Number and Electron Configuration
- Tin has the atomic number 50.
- The electron configuration of tin can be written as:
\[ \text{[Kr]} \, 4d^{10} \, 5s^{2} \, 5p^{2} \]

### Step 2: Determine the Block
- The block of an element is determined by the type of orbital that contains its valence electrons.
- In the case of tin, the valence electrons are in the 5s and 5p orbitals. Since the outermost electrons are in the p orbital, tin is classified as a **p-block element**.

### Step 3: Determine the Period
- The period of an element corresponds to the highest principal quantum number (n) of its valence electrons.
- For tin, the highest principal quantum number in its electron configuration is 5 (from the 5s and 5p orbitals).
- Therefore, tin belongs to **period 5**.

### Step 4: Determine the Group
- For p-block elements, the group number can be calculated using the formula:
\[ \text{Group} = \text{Number of valence electrons} + 10 \]
- Tin has 4 valence electrons (2 from 5s and 2 from 5p).
- Applying the formula:
\[ \text{Group} = 4 + 10 = 14 \]
- Thus, tin belongs to **group 14**.

### Final Summary
- Tin (Sn) is a **p-block** element, located in **period 5**, and belongs to **group 14**.

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