Which of the following structures correspond to the product expected, when excess of `C_(6)H_(6)` reacts with `CH_(2)Cl_(2)` in presence of anhydrous `AlCl_(3)`.

Options

A.
B.
C.
D.

Explanation

To solve the problem, we need to understand the reaction taking place between benzene (C₆H₆) and dichloroethane (CH₂Cl₂) in the presence of anhydrous aluminum chloride (AlCl₃). This reaction is an example of Friedel-Crafts alkylation.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have benzene (C₆H₆) and dichloroethane (CH₂Cl₂) as our reactants.
- Anhydrous aluminum chloride (AlCl₃) acts as a catalyst.

2. **Understand the Reaction Type**:
- This reaction is a Friedel-Crafts alkylation, which involves the substitution of hydrogen in benzene with an alkyl group from the alkyl halide (dichloroethane in this case).

3. **Formation of the Electrophile**:
- In the presence of AlCl₃, dichloroethane can form a carbocation (the electrophile) by losing a chloride ion (Cl⁻).
- The reaction can be represented as:
\[ \text{CH}_2\text{Cl}_2 + \text{AlCl}_3 \rightarrow \text{C}_2\text{H}_5^+ + \text{AlCl}_4^- \]
- Here, the ethyl cation (C₂H₅⁺) is formed.

4. **Electrophilic Aromatic Substitution**:
- The ethyl cation (C₂H₅⁺) will then react with benzene (C₆H₆) through electrophilic aromatic substitution.
- The reaction can be represented as:
\[ \text{C}_6\text{H}_6 + \text{C}_2\text{H}_5^+ \rightarrow \text{C}_6\text{H}_5\text{C}_2\text{H}_5 \]
- This results in the formation of diphenylmethane (C₆H₅-CH₂-C₆H₅).

5. **Byproducts**:
- Along with diphenylmethane, hydrochloric acid (HCl) is produced as a byproduct:
\[ \text{HCl} \text{ is released during the reaction.} \]

6. **Final Product**:
- The final product of the reaction is diphenylmethane (C₆H₅-CH₂-C₆H₅).

### Conclusion:
The product expected when excess benzene reacts with dichloroethane in the presence of anhydrous AlCl₃ is diphenylmethane.