Standard reduction potentials of the hal...

Standard reduction potentials of the half reactions are given below
`{:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):}`
The strongest oxidising and reducing agents respectively are

`Cl_(2) and Br^(-)`

`Cl_(2) and I_(2)`

`F_(2) and I^(-)`

`Br_(2) and Cl^(-)`

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Standard reduction potentials of the half reactions are given below: F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87 Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V The strongest oxidizing and reducing agents respectively are:

Standard reduction potentails of the half reactions are given below: F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87 Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V The strongest oxidizing and reducing agents respectively are:

Standard reduction potential of the half cell reactions are given below Co^(3+)(aq) + e^(1-) to Co^(2+)(aq) , E^0 = +1.81 V Au^(3+)(aq) + 3e^(1-) to Au(s) , E^0 = +1.40 V I_(2)(s) + 2e^(1-) to 2I^(-)(aq) , E^0 = +0.54 V Cu^(2+)(aq) + 2e^(1-) to Cu(s) , E^0 = +0.34 V The strongest oxidizing and reducing agents respectively are:

The standard reduction potential at 298 K for the following half reactions are given below: Fe^(3+)(1M)+e^(-)rarrFe^(2+)(aq),E^(o)=0.770 V, Zn^(2+)(1M)+2e^(-)rarrZn(s),E^(o)=-0.762 V Cd^(2+)(1M)+2e^(-)rarrCd(s),E^(o)=-0.402 V, 2H^(+)(1M)+2e^(-)rarrH_(2)(g),E^(o) = 0.00 V. The strpongest reducing agent is:

Based on the data given below, the correct order of reducing power is: Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V

Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titration. Some half cell reaction and their standard potentials are given below: MnO_(4)^(-)(aq) +8H^(+)(aq) +5e^(-) rarr Mn^(2+)(aq) +4H_(2)O(l) E^(@) = 1.51V Cr_(2)O_(7)^(2-)(aq) +14H^(+) (aq) +6e^(-) rarr 2Cr^(3+)(aq) +7H_(2)O(l), E^(@) = 1.38V Fe^(3+) (aq) +e^(-) rarr Fe^(2+) (aq), E^(@) = 0.77V CI_(2)(g) +2e^(-) rarr 2CI^(-)(aq), E^(@) = 1.40V Identify the only correct statement regarding quantitative estimation of aqueous Fe(NO_(3))_(2)

E^(c-) of some elements are given as : {:(I_(2)+2e^(-)rarr 2I^(c-),,,,E^(c-)=0.54V),(MnO_(4)^(c-)+8H^(o+)+5e^(-)rarr Mn^(2+)+4H_(2)O,,,,E^(c-)=1.52V),(Fe^(3+)+e^(-)rarr Fe^(2+),,,,E^(c-)=0.77V),(Sn^(4+)+2e^(-)rarr Sn^(2+),,,,E^(c-)=0.1V):} Select the strongest oxidant and weakest oxidant among these elements.

The standard electrode potential of the half cells are given below : Zn^(2+)+ 2e^(-) rarr Zn(s), E^(o) = - 7.62 V Fe^(2+) + 2e^(-) rarr Fe(s) , E^(o) = -7 .81 V The emf of the cell Fe^(2+) + Zn rarr Zn^(2+) + Fe will be :

Given below are a set of half-cell reactions (acidic medium) along with their E_(@) with respect to normal hydrogen electrode values. Using the data obtain the correct explanation to question given below. {:(I_(2)+2e^(-)rarr2I^(-),E^(@)=0.54),(Cl_(2)+2e^(-)rarr2Cl^(-),E^(@)=1.36),(Mn^(2+)+e^(-)rarrMn^(2+),E^(@)=1.50),(Fe^(3+)+e^(-)rarrFe^(2+),E^(@)=0.77),(O_(2)+4H^(+)+4e^(-)rarr2H_(2)O,E^(@)=1.23):} Among the following, identify the correct statement:

Knowledge Check

Based on the data given below, the correcy order of reducing power is: Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V

`Br^(-) lt Fe^(2+) lt Al`

`Fe^(2+) lt Al lt Br^-`

`Al lt Br^(-) lt Fe^(2+)`

`Al lt Fe^(2+) lt Br^(-)`

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