When phenol is allowed to react with `Br_(2)` in (i) `CS_(2)` solution and (ii) in aqueous solution, the resulting compounds are

Options

A. (i) 2, 4, 6-tribromophenol and (ii) o- and p-bromophenol
B. (i) m-bromophenol and (ii) 2, 3, 4-tribromophenol
C. (i) o- and p-bromophenol and (ii) 2, 4, 6-tribromophenol
D. (i) o- and m-bromophenol and (ii) 2, 3, 4-tribromophenol

Answer

To solve the question regarding the reaction of phenol with \( Br_2 \) in two different solvents, we can break it down into steps.

### Step-by-Step Solution:

1. **Identify the Reactant**: The reactant in both cases is phenol, which has the structure \( C_6H_5OH \).

2. **Reaction with \( Br_2 \) in \( CS_2 \)**:
- When phenol reacts with bromine (\( Br_2 \)) in carbon disulfide (\( CS_2 \)), it undergoes electrophilic aromatic substitution.
- The hydroxyl group (-OH) on phenol is an activating group and directs the incoming bromine to the ortho and para positions relative to itself.
- Therefore, the products formed are:
- Ortho-bromophenol (1-bromo-2-hydroxybenzene)
- Para-bromophenol (1-bromo-4-hydroxybenzene)

3. **Reaction with \( Br_2 \) in Aqueous Solution**:
- When phenol reacts with bromine in an aqueous solution, the reaction is more vigorous due to the presence of water.
- In this case, phenol will react with three equivalents of bromine, resulting in the substitution of all available hydrogen atoms on the aromatic ring.
- The product formed is 2,4,6-tribromophenol (2,4,6-tribromo-phenol), where bromine atoms are substituted at the 2, 4, and 6 positions of the benzene ring.

4. **Summarizing the Products**:
- In \( CS_2 \): Ortho-bromophenol and Para-bromophenol.
- In aqueous solution: 2,4,6-tribromophenol.

### Final Answer:
- The resulting compounds are:
- (i) Ortho-bromophenol and Para-bromophenol in \( CS_2 \) solution.
- (ii) 2,4,6-tribromophenol in aqueous solution.