Five persons A,B,C,D and E are standing in a queve of a ration shop . The probability that A and R are always togethar is .

Options

A. `(1)/(4)`
B. `(2)/(3)`
C. `(2)/(5)`
D. `(3)/(5)`

Answer

C

Explanation

5 persons A, B, C, D and E can stand in a queue in 5! Ways.
Persons A and E can occur together in 2! Ways.
Considering A and E as one person, there are 4 persons who can be queued in 4! Ways.
So, A and E can occur together in `4!xx2!` ways.
So, required probability `=(4!xx2!)/(5!)=(2)/(5)`