Home
Class 8
MATHS
Find the least square number which is ex...

Find the least square number which is exactly divisible by 3, 4, 5, 6 and 8.

A

360

B

240

C

160

D

120

Text Solution

AI Generated Solution

The correct Answer is:
To find the least square number that is exactly divisible by 3, 4, 5, 6, and 8, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Numbers**: The numbers we need to consider are 3, 4, 5, 6, and 8. 2. **Prime Factorization**: - 3 is a prime number: \(3 = 3^1\) - 4 can be factored into primes: \(4 = 2^2\) - 5 is a prime number: \(5 = 5^1\) - 6 can be factored into primes: \(6 = 2^1 \times 3^1\) - 8 can be factored into primes: \(8 = 2^3\) 3. **List the Prime Factors**: - From the factorizations, we have: - \(2\) appears in \(4\) (as \(2^2\)), \(6\) (as \(2^1\)), and \(8\) (as \(2^3\)). - \(3\) appears in \(3\) (as \(3^1\)) and \(6\) (as \(3^1\)). - \(5\) appears in \(5\) (as \(5^1\)). 4. **Determine the LCM**: - The LCM is found by taking the highest power of each prime factor: - For \(2\): the highest power is \(2^3\) (from 8). - For \(3\): the highest power is \(3^1\) (from 3 and 6). - For \(5\): the highest power is \(5^1\) (from 5). - Therefore, the LCM is: \[ \text{LCM} = 2^3 \times 3^1 \times 5^1 = 8 \times 3 \times 5 \] 5. **Calculate the LCM**: - First, calculate \(8 \times 3 = 24\). - Then, calculate \(24 \times 5 = 120\). - So, the LCM of 3, 4, 5, 6, and 8 is \(120\). 6. **Adjust for Square Number**: - A square number must have even powers for all prime factors. - The LCM \(120\) can be expressed in prime factorization as: \[ 120 = 2^3 \times 3^1 \times 5^1 \] - To convert this into a square number, we need to make the powers even: - For \(2^3\), the next even power is \(2^4\). - For \(3^1\), the next even power is \(3^2\). - For \(5^1\), the next even power is \(5^2\). 7. **Form the Square Number**: - The least square number is: \[ \text{Least Square Number} = 2^4 \times 3^2 \times 5^2 \] 8. **Calculate the Least Square Number**: - Calculate \(2^4 = 16\), \(3^2 = 9\), and \(5^2 = 25\). - Now, multiply these together: \[ 16 \times 9 = 144 \] \[ 144 \times 25 = 3600 \] 9. **Final Answer**: - The least square number which is exactly divisible by 3, 4, 5, 6, and 8 is \(3600\).
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SQUARE - SQUARE ROOT AND CUBE-CUBE ROOT

    NCERT EXEMPLAR|Exercise Exercise (Solve the following questions.)|9 Videos
  • RATIONAL NUMBERS

    NCERT EXEMPLAR|Exercise Think and Discuss |1 Videos
  • UNDERSTANDING QUADRILATERALS AND PRACTICAL GEOMETRY

    NCERT EXEMPLAR|Exercise THINK AND DISCUSS|2 Videos

Similar Questions

Explore conceptually related problems

Find the least square number which is exactly divisible by 10,12,15 and 18.

Find the least number which is exactly divisible by 32,36,45,60 and 80 .

Knowledge Check

  • Find the least square number which is exactly divisible by 4, 9 and 14.

    A
    1008
    B
    252
    C
    1764
    D
    504
  • Find the least square number which is divisible by 3, 5, 6, and 9.

    A
    900
    B
    90
    C
    8100
    D
    81
  • The least perfect square number which is divisible by 3, 4, 5, 6, and 8 is-

    A
    900
    B
    1200
    C
    25
    D
    3600
  • Similar Questions

    Explore conceptually related problems

    Find the least square number which is exactly divisible by each of the numbes 8,12,15 and 20.

    Find the least 5-digit number which is exactly divisible by 20, 25, 30.

    Find the least square number which is divisible by 4, 8, 2, 6 and 12?

    The least perfect square number which is divisible by 3,4,5,6 and 8 is

    The least square number exactly divisible by 4,6,10,15 is