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The amount of water vapour produced by t...

The amount of water vapour produced by the combustion of 16 g of methane is

A

16 g

B

36 g

C

18 g

D

32 g

Text Solution

Verified by Experts

The correct Answer is:
B
The balanced equation for combustion of methane is
` CH_(4 (g)) + 2O_(2 (g)) to CO_(2 (g)) + 2H_2 O_((g))`
16 g of `CH_4` corresponds to one mole. From the above equation, 1 mole of `CH_(4(g))` gives 2 moles of `H_2 O_((g))`
2 moles of water `(H_2O) = 2 xx(2 + 16) = 2 xx 18 = 36 g`
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Knowledge Check

  • Calculate the amount of CO_(2(g)) produced by combustion of 32 g of oxygen.

    A
    22 g
    B
    240 g
    C
    21g
    D
    32 g

  • The heat of combustion of methane is -880 KJ mol^(-1) . The quantity of heat liberated in the combustion of 3.2 g methane is

    A
    `-88 KJ`
    B
    `+88 KJ`
    C
    `+176 KJ`
    D
    `-176 KJ`

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