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The amount of water vapour produced by t...

The amount of water vapour produced by the combustion of 16 g of methane is

A

16 g

B

36 g

C

18 g

D

32 g

Text Solution

Verified by Experts

The correct Answer is:
B
The balanced equation for combustion of methane is
` CH_(4 (g)) + 2O_(2 (g)) to CO_(2 (g)) + 2H_2 O_((g))`
16 g of `CH_4` corresponds to one mole. From the above equation, 1 mole of `CH_(4(g))` gives 2 moles of `H_2 O_((g))`
2 moles of water `(H_2O) = 2 xx(2 + 16) = 2 xx 18 = 36 g`
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