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1.0 g of magnesium is burnt with 0.56 g ...

1.0 g of magnesium is burnt with 0.56 g `O_2` in a closed vessel. Which reactant is left in excess and how much? (At. wt. Mg = 24, O=16)

A

Mg, 0.16 g

B

`O_2`, 0.16 g

C

Mg, 0.44 g

D

`O_2 ,`0.28 g

Text Solution

Verified by Experts

The correct Answer is:
A
`n_(Mg) = (1)/(24 ) = 0.416 mol , n_(O_2) = ( 0.56 )/(32) = 0.0175 mol`
The balanced equation is

here ` O_2 ` is a limiting agent .
` therefore ` Mass of Mg left in excess `= 0.0066 xx 24 = 0.16 g `
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Knowledge Check

  • 1.0 g of magnesium is burnt with 0.56 g O_(2) in a closed vessel. Which reactant is left in excess and how much ? (At. Wt. of Mg = 24, O = 16)

    A
    Mg, 0.16 g
    B
    `O_(2),0.16g`
    C
    `Mg,0.44g`
    D
    `O_(2),0.28g`

  • 1.0 g of magnesium is burnt with 0.56 g of O_(2) in a closed vessel. Which reactant is left in excess and how much ?

    A
    Mg , 0.44 g
    B
    `O_(2)` , 0.28 g
    C
    Mg , 0.16 g
    D
    `O_(2)` , 0.16 g

  • 1.0 gof magnesium is burnt with 0.56 g O_(2) in a closed vessel. Which treatment is left in excess and how much? (At wt. Mg=24,O=16 )

    A
    Mg, 0.16
    B
    `O_(2)`,0.16g
    C
    Mg,0.44g
    D
    `O_(2),` 0.28 g

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