What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO, is mixed with 50 mL of 5.8% NaCl solution? (Ag = 107.8, N = 14,0 = 16, Na - 23, C1= 35.5)

Options

A. 3.5 g
B. 7 g
C. 14 g
D. 28 g

Answer

B

Explanation

16.9% solution of `AgNO_3` means 16.9 g of `AgNO_3` in 100 mL of solution. 16.9 g of AgNO, in 100 mL solution = 8.45 g of `AgNO_3` in 50 mL solution. Similarly, 5.8% of NaCl in 100 mL solution = 2.9 g of NaCl in 50 mL solution. The reaction can be represented as:

` therefore ` mass of AgCl precipitared `= 0.049 xx 143.3 =7.02 ~~ 7 g `