In which case is number of molecules of water maximum?

Options

A. 18 mL of water
B. 0.18 g of water
C. 0.00224 L of water vapours at 1 atm and 273 K
D. `10^(-3) `mol of water

Answer

A

Explanation

(a) Mass of water `=V xx d= 18 × 1 = 18 g `
Molecules of water = mole `xx N_A = (18)/(18) N_A = N_A`
(b) Molecules of water = mole `xx N_A= (0.18 )/(18 ) N_A = 10^(-2) N_A`
(c) Moles of water` = (0.00224)/(22.4 ) =10^(-4)`
Molecules of water = mole `xx N_A = 10^(-4) N_A`
(d) Molecules of water = mole ` xx N_A = 10^(-3) N_A `