Home
Class 11
MATHS
Let A={1,2,3ddot, 14} . Define a relatio...

Let `A={1,2,3ddot, 14}` . Define a relation on a set A by `R={(x , y):3x-y=0. w h e r e\ x , y in A}` . Depict this relationship using an arrow diagram. Write down its domain, co-domain and range.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Define the Set A We start with the set \( A = \{1, 2, 3, \ldots, 14\} \). ### Step 2: Define the Relation R The relation \( R \) is defined by the equation \( 3x - y = 0 \) or equivalently \( y = 3x \). Here, \( x \) and \( y \) are elements of set \( A \). ### Step 3: Find Ordered Pairs in R We will find the ordered pairs \( (x, y) \) such that both \( x \) and \( y \) belong to set \( A \). - For \( x = 1 \): \( y = 3(1) = 3 \) → Pair: \( (1, 3) \) - For \( x = 2 \): \( y = 3(2) = 6 \) → Pair: \( (2, 6) \) - For \( x = 3 \): \( y = 3(3) = 9 \) → Pair: \( (3, 9) \) - For \( x = 4 \): \( y = 3(4) = 12 \) → Pair: \( (4, 12) \) - For \( x = 5 \): \( y = 3(5) = 15 \) → 15 is not in A, so we stop here. - Continuing with \( x = 6, 7, \ldots, 14 \) will yield \( y \) values greater than 15, which are also not in A. Thus, the relation \( R \) consists of the pairs: \[ R = \{(1, 3), (2, 6), (3, 9), (4, 12)\} \] ### Step 4: Draw the Arrow Diagram In the arrow diagram, we will represent the elements of set \( A \) on one side and their corresponding \( y \) values on the other side: ``` 1 → 3 2 → 6 3 → 9 4 → 12 ``` ### Step 5: Determine Domain, Co-domain, and Range - **Domain**: The set of all \( x \) values that have corresponding \( y \) values in the relation. From our pairs, the domain is: \[ \text{Domain} = \{1, 2, 3, 4\} \] - **Co-domain**: The set from which \( y \) values are taken. Since \( y \) values are derived from set \( A \), the co-domain is: \[ \text{Co-domain} = A = \{1, 2, 3, \ldots, 14\} \] - **Range**: The set of all \( y \) values that are actually produced by the relation. From our pairs, the range is: \[ \text{Range} = \{3, 6, 9, 12\} \] ### Summary of Results - **Relation R**: \( \{(1, 3), (2, 6), (3, 9), (4, 12)\} \) - **Domain**: \( \{1, 2, 3, 4\} \) - **Co-domain**: \( \{1, 2, 3, \ldots, 14\} \) - **Range**: \( \{3, 6, 9, 12\} \)

To solve the problem, we will follow these steps: ### Step 1: Define the Set A We start with the set \( A = \{1, 2, 3, \ldots, 14\} \). ### Step 2: Define the Relation R The relation \( R \) is defined by the equation \( 3x - y = 0 \) or equivalently \( y = 3x \). Here, \( x \) and \( y \) are elements of set \( A \). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 2.3|5 Videos
  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|12 Videos
  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 2.1|10 Videos
  • PROBABILITY

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|10 Videos
  • SEQUENCE AND SERIES

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|32 Videos

Similar Questions

Explore conceptually related problems

Let A={1,2,3,..., 14} . Define a relation on a set A by R={(x , y):3x-y=0. w h e r e\ x , y in A} . Depict this relationship using an arrow diagram. Write down its domain, co-domain and range.

Let A = {1, 2, 3, 4, 5, 6} . Define a relation R from A to A by R = {(x , y) : y = x +1} (i) Depict this relation using an arrow diagram.(ii) Write down the domain, co-domain and range of R.

Knowledge Check

  • If A = {2,3,4,5,6) and R is a relation on set A defined by R= {(x, y): y=x+2, X, y in A} then

    A
    {(2,4), (3,5), (4, 6)}
    B
    {(4,2), (5,3), (6,4)}
    C
    {(2,4), (5,3), (4, 6)}
    D
    {(4,2), (3,5),(4,6)}
  • Let A = {1,2,3,4,5,6} and R be the relation defined on A by R = {(x, y): x, y in A, x divides y}, then range of R is

    A
    {2,3,4,5,6}
    B
    (1,2,3,4,5)
    C
    {2,4,6}
    D
    {1,2,3,4,5,6}
  • Similar Questions

    Explore conceptually related problems

    Let A={1,2,3,4,5,6}dot Define a relation R on set A by R={(x , y): y=x+1} Depict this relation using an arrow diagram Write down the domain, co domain and range of Rdot

    Let A = {1, 2, 3, 4, 5, 6}. Define a relation R from A to A by R = {(x, y) : y = x+1}.

    Let A = {1, 2, 3, ... , 14} . Define a relation R from A to A by R = {(x , y) : 3x - y = 0, " where " x , y in A} . Write down its domain, co-domain and range.

    Define a relation R on the set N of natural numbers by R={(x , y): y=x+5, x is a natural number less than 4, x , y in N} . Depict this relationship using i. roster form ii. an arrow diagram. Write down the domain and range or Rdot

    Define a relation R on the set N of natural numbers by R = {(x , y) : y = x + 5 , x is a natural number less than 4; x, y in N} . Depict this relationship using roster form. Write down the domain and the range...

    Define a relation R on the set N of natural numbers by R" "=" "{(x ," "y)" ":" "y" "=" "x" "+" "5 , x is a natural number less than 4; x, y in N }. Depict this relationship using roster form. Write down the domain and the range.