Home
Class 9
MATHS
In the adjoining figure, BD = DC and AE ...

In the adjoining figure, BD = DC and AE = ED. Prove that
area of `DeltaACE = (1)/(4) " area of " DeltaABC`

Promotional Banner

Topper's Solved these Questions

  • AREA OF PARALLELOGRAMS AND TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (long Answer Question)|5 Videos

  • AREA OF PARALLELOGRAMS AND TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (very Short Answer Questions)|10 Videos

  • CIRCLE

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (long Answer Questions )|5 Videos

Similar Questions

Explore conceptually related problems

In the adjoining figure, DE || BC . Prove that area (DeltaACD) = " area " (DeltaABE)

In the adjoining figure, AD = DC and DB bisects angleADC . Prove that DeltaADB cong DeltaCDB .

In the adjoining figure, D is the mid-point of side AB of Delta ABC and P be any point on side BC. If CQ ||PD , then prove that: area of Delta BPQ = (1)/(2) xx " area of " Delta ABC

In the given figure AB=AC and AD=AE. Prove that (i) DeltaABD~=DeltaACE and (ii) BE=DC

The base BC of triangle ABC is divided at D so that BD = (1)/(2) DC. Prove that area of DeltaABD=(1)/(3) of the area of DeltaABC .

In triangle ABC, D is a point in side BC such that 2BD=3DC . Prove that the area of triangle ABD = (3)/(5)xx "Area of" DeltaABC

ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y. Prove that area of DeltaADX = area of DeltaACY .

ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y. Prove that area of DeltaADX = area of DeltaACY .

In the given figure, DE // BC and AE : EC = 5 : 4. Find : area of DeltaDOE : area of DeltaOCB

In the adjoining figure, angleBAC=angleBDC and angleABC=angleBCD . Prove that : (i) DeltaABC cong DeltaDCB (ii) DeltaABE cong DeltaDCF .