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both roots of the equation (x-a)(x-b)+(x...

both roots of the equation `(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0` are

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To solve the equation \((x-a)(x-b) + (x-b)(x-c) + (x-c)(x-a) = 0\) and determine the nature of its roots, we can follow these steps: ### Step 1: Expand the Equation First, we need to expand each term in the equation: 1. Expand \((x-a)(x-b)\): \[ (x-a)(x-b) = x^2 - (a+b)x + ab ...
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