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The formation of the oxide ion O((g))^(2...

The formation of the oxide ion `O_((g))^(2-)` requires first an exothermic and then an endothermic step as shown below.
`O_((g)) +e^(-) = O_((g))^(-) DeltaH^(@) =- 142 kJ mol^(-1)`
`O_((g))^(-) + e^(-) = O_((g))^(2-) DeltaH^(@) = 844 kJ mol^(-1)` This is because of :

A

Oxygen is more electronegative.

B

Oxygen has high electron affinity.

C

`O^(-)` ion has comparatively larger size than oxygen atom.

D

`O^(-)` ion will tend to resist the addition of electron.

Text Solution

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The correct Answer is:
A, B
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Knowledge Check

  • The formation of the oxide ion O_((g))^(2-) requires first an exothermic and then an endothermic step as shown below: O_((g)) +e^(-) rarr O_((g))^(-), DeltaH =- 142 kj mol^(-1) O_((g))^(-) + e^(-) rarr O_((g))^(2-), DeltaH = 844 kj mol^(-1) This is because:

    A
    `O^(-)` ion has comparatively larger size than oxygen atom
    B
    Oxygen has high electron affinity
    C
    `O^(-)` ion will tend to resist the addition of another electron
    D
    Oxygen is more electronegative

  • The formation of the oxide ion O_((g))^(2-) requires first an exothermic and then an endothermic step as shown below O_((g))+e^(-)= O_((g))^(-) DeltaH^(@)= -142 " kJ mol"^(-1) O^(-)(g)+e^(-) = O_((g))^(2-) DeltaH^(@)=844 " kJmol"^(-1) This is because

    A
    `O^(-)` ion will tend to resist the addition of another electron
    B
    Oxygen has high electron affinity
    C
    Oxygen is more electronegative
    D
    `O^(-)` ion has comparatively larger size than oxygen atom

  • The formation of the oxide ion O_(g)^(2-) requires first an exothermic and then an endothermic step as shown below: O_(g)+e^(-) = O_(g)^(-), DeltaH^(@)=-142 kJmol^(-1) O_(g)^(-)+e^(-) = O_(g)^(2-), DeltaH^(@)= 844 kJmol^(-1) This is because

    A
    `O^(-)` ion will tend to resist the addition of another electron
    B
    oxygen has high electron affinity
    C
    oxygen is more electronegative
    D
    `O^(-)` ion has comparatively larger size than oxygen atom.

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