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5 moles of SO2 and 5 moles of O2 are all...

5 moles of `SO_2` and 5 moles of `O_2` are allowed to react to form `SO_3` in a closed vessel. At the equilibrium stage, 60% `SO_2` is used up. The total number of moles of `SO_2, O_2, and SO_3,` in the vessel at equilibrium is

A

10.5

B

10

C

8.5

D

3.9

Text Solution

Verified by Experts

The correct Answer is:
C
`2SO_(2) +O_(2) Leftrightarrow 2SO_#`
2 mole of `SO_2` react with 1 mole of `O_2` to give 2 moles of `SO_3`
`"Initial moles "underset(5)(2SO_2)+underset(5)(O_2) Leftrightarrow underset(0)(2SO_3)`
`"At equilibrium "5-5 xx (60)/(100) " "5-3/2 " 3"`
`=5-3=2 " =3.5"`
Total moles =2+3.5 +3=8.5
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Knowledge Check

  • 5 moles of SO_(2) and 5 moles of O_(2) are allowed to react to form SO_(3) in a closed vessel. At the equilibrium stage, 60%SO_(2) is used up. The total number of moles of SO_(2),O_(2)andSO_(3) in the vessel now is

    A
    `3.9`
    B
    `10.5`
    C
    `8.5`
    D
    `10.0`

  • 5 moles of SO_(2) and 5 moles of O_(2) are allowed to react to form SO_(3) in a closed vessel. At the equilibrium stage 60% of SO_(2) is used up. The total number of moles of SO_(2), O_(2) and SO_(3) in the vessel now is

    A
    `10.0`
    B
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    `10.0`
    B
    `8.5`
    C
    `10.5`
    D
    `3.9`

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