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20.0 g of a magnesium carbonate sample d...

20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample? (At. wt. of Mg = 24)

A

96

B

60

C

84

D

75

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(84g)(MgCO_(3(s))) overset(Delta)to underst(40g)(MgO_(s))) + CO_(2(g))`
84g of `MgCO_3 -= ` 40 g of `MgO`
`:.` 20 g of `MgCO_3 = (40)/(84) xx 20 = 9.52g ` of MgO
Actual yield = 8g of MgO
`:.` % Purity`=(8)/(9.52) xx 100 = 84%`
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