The number of Faradays (F) required to produce 20 g of calcium from molten `CaCl_(2)` (Atomic mass of Ca = 40 g `mol^(-1)`) is
A
1
B
2
C
3
D
4
Text Solution
Verified by Experts
The correct Answer is:
A
`Ca_((aq))^(2+)+underset(underset(1F)(2F))(2e^(-)) rarr underset(underset(20g)("1 mole =40 g"))(Ca_((s)))` Thus, one Faraday is required to produce 20 g of calcium from molten `CaCl_(2)`.
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Knowledge Check
The number of Faraday.s (F) required to produce 20 g of calcium from CaCl_(2) (Atomic mass of Ca= 40 g "mol"^(-1) is:
A
2
B
3
C
4
D
1
The number of Faraday.s (F) required to produce 20 g of calcium from CaCl_(2) (Atomic mass of Ca= 40 g "mol"^(-1) is:
A
2
B
3
C
4
D
1
Number of Faraday's required to generate one gram atom of calcium from molten CaCl-2 is
A
1
B
2
C
3
D
4
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