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cot^(-1)[(cos alpha)^(1//2)]-tan^(-1)[(c...

`cot^(-1)[(cos alpha)^(1//2)]-tan^(-1)[(cos alpha)^(1//2)]=x` then `sin x`=

A

`tan^(2) (alpha//2)`

B

`cot^(2) (alpha//2)`

C

`tan alpha`

D

`cot(alpha//2)`

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The correct Answer is:
A
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