In the hydroboration-oxidation reaction of Propene with diborane, `H_2O_2` and `NaOH`, the organic compound formed is

Options

A. `CH_(3) CH_2 CH_2 OH`
B. `CH_3 CH_(2) OH`
C. `(CH_(3))_(3)COH`
D. `CH_3 CHOHCH_3`

Answer

To solve the question regarding the hydroboration-oxidation reaction of propene with diborane and the subsequent formation of an organic compound, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are propene (C3H6), diborane (B2H6), hydrogen peroxide (H2O2), and sodium hydroxide (NaOH).

2. **Hydroboration Step**:
In the hydroboration step, diborane (B2H6) reacts with propene. The boron atom adds to the less substituted carbon of the double bond in propene due to the anti-Markovnikov addition. The initial product formed is an organoborane compound.

- Reaction:
\[ \text{C}_3\text{H}_6 + \text{B}_2\text{H}_6 \rightarrow \text{C}_3\text{H}_7\text{B} \]

3. **Formation of Trialkyl Borane**:
The organoborane compound can further react with additional propene molecules. This results in the formation of a trialkyl borane where three propyl groups are attached to boron.

- Reaction:
\[ \text{C}_3\text{H}_7\text{B} + \text{2C}_3\text{H}_6 \rightarrow \text{C}_9\text{H}_{21}\text{B} \]

4. **Oxidation Step**:
The next step involves the oxidation of the trialkyl borane using hydrogen peroxide (H2O2) in the presence of a base (NaOH). The boron atom is replaced by a hydroxyl group (OH) during this oxidation process.

- Reaction:
\[ \text{C}_9\text{H}_{21}\text{B} + \text{H}_2\text{O}_2 + \text{NaOH} \rightarrow \text{C}_9\text{H}_{22}\text{O} + \text{B(OH)}_3 \]

5. **Final Product**:
The final product formed from the hydroboration-oxidation of propene is propanol (specifically, 1-propanol or n-propanol), which has the molecular formula C3H8O.

### Conclusion:
The organic compound formed from the hydroboration-oxidation reaction of propene with diborane, H2O2, and NaOH is **propanol** (C3H8O).