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The radius of Na^(+) is 95pm and that of...

The radius of `Na^(+)` is 95pm and that of `Cl^(-)` is 181 pm. The edge length of unit cell in NaCl would be (pm).

A

276pm

B

138 pm

C

552 pm

D

415 pm

Text Solution

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The correct Answer is:
C
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The radius of Na^(+) ion is 95 pm and that of Cl^(-) ion is 181 pm. Predict the structure of Na^(+)Cl^(-) and the coordination number of cation.

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Knowledge Check

  • If the distance between Na^(+) and Cl^(-) ions in NaCl crystals is 265 pm, then edge length of the unit cell will be ?

    A
    265 pm
    B
    795 pm
    C
    132.5 pm
    D
    530 pm
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