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Metal M+"air" overset(delta)(to)Aoverset...

Metal `M+"air" overset(delta)(to)Aoverset(H_(2)O)(to)Boverset(HCl)(to)` White fumes, Metal M can be:

A

`Le, Mg or Al`

B

`Li, Al or K`

C

`Na, K or Mg`

D

`Li, Na or K`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the metal \( M \) that reacts with air to form a compound \( A \), which upon hydrolysis with water forms a compound \( B \), and then reacts with hydrochloric acid (HCl) to produce white fumes. The presence of white fumes indicates the formation of ammonium chloride (NH4Cl). ### Step-by-Step Solution: 1. **Identify the Reaction with Air**: - Metal \( M \) reacts with air. This generally means it reacts with oxygen and possibly nitrogen. - The product \( A \) formed could be a metal oxide or a metal nitride. 2. **Hydrolysis with Water**: - The product \( A \) then reacts with water to form \( B \). - Since we are looking for a compound that can lead to the formation of ammonia (NH3), \( B \) must be a compound that can produce ammonia upon hydrolysis. 3. **Reaction with HCl**: - The compound \( B \) reacts with HCl to produce white fumes, which indicates the formation of ammonium chloride (NH4Cl). - This suggests that \( B \) must contain nitrogen in a form that can yield ammonia. 4. **Possible Metals**: - We consider metals that can react with air to form nitrides or oxides that can hydrolyze to produce ammonia. - Magnesium (Mg), Lithium (Li), and Aluminum (Al) are potential candidates because they can form nitrides or hydroxides that can react with HCl to produce NH4Cl. 5. **Verification**: - Let's verify with Magnesium: - \( \text{Mg} + \text{O}_2 \rightarrow \text{MgO} \) (or possibly a nitride) - \( \text{MgO} + \text{H}_2O \rightarrow \text{Mg(OH)}_2 \) (or a reaction leading to NH3) - \( \text{Mg(OH)}_2 + \text{HCl} \rightarrow \text{NH}_4\text{Cl} \) (producing white fumes) - Similar reactions can be checked for Lithium and Aluminum. 6. **Conclusion**: - Since all three metals (Mg, Li, Al) can lead to the formation of white fumes through the production of NH4Cl, we conclude that the metal \( M \) can be Magnesium, Lithium, or Aluminum. ### Final Answer: The metal \( M \) can be: **Magnesium (Mg), Lithium (Li), or Aluminum (Al)**.
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Knowledge Check

  • Element M+N_(2) overset(Delta)to overset(H_(2)O)toNH_(3) element M belonging to group 13 can be

    A
    B or Al
    B
    Ga or Al
    C
    B or Ga
    D
    In or Tl
  • Consider the following sequence of reactions CH_(3)-overset(O)overset(||)(C)-CH_(3)overset(Ba(OH)_(2))(to)Aoverset(Delta)(to)underset(darr NaBH_(4))(B) The final product (C) is:

    A
    `(CH_(3))_(2)C(OH)CH_(2)COCH_(3)`
    B
    `(CH_(3))_(2)C=CHCOCH_(3)`
    C
    `(CH_(3))_(2)CHCH_(2)CHOHCH_(3)`
    D
    `(CH_(3))_(2)C=CHCHOHCH_(3)`
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