Total number of low spin complexes are `[Fe(CN)_6^(3-),[Co(NO_2)_6]^(3-),[FeF_6]^(3-)[IrF_6]^(3-),[Co(NH_3)_6]^(3+),[Co(H_2O)_6]^(+2),[Mn(H_2O)_6]^(3+)`

Answer

To determine the total number of low spin complexes from the given list, we need to analyze each complex based on the nature of the ligands and the oxidation states of the central metal ions.

### Step-by-Step Solution:

1. **Identify the complexes and their ligands**:
- `[Fe(CN)6]^(3-)`
- `[Co(NO2)6]^(3-)`
- `[FeF6]^(3-)`
- `[IrF6]^(3-)`
- `[Co(NH3)6]^(3+)`
- `[Co(H2O)6]^(2+)`
- `[Mn(H2O)6]^(3+)`

2. **Determine the oxidation states of the central metal ions**:
- For `[Fe(CN)6]^(3-)`: Iron (Fe) is in +3 oxidation state.
- For `[Co(NO2)6]^(3-)`: Cobalt (Co) is in +3 oxidation state.
- For `[FeF6]^(3-)`: Iron (Fe) is in +3 oxidation state.
- For `[IrF6]^(3-)`: Iridium (Ir) is in +3 oxidation state.
- For `[Co(NH3)6]^(3+)`: Cobalt (Co) is in +3 oxidation state.
- For `[Co(H2O)6]^(2+)`: Cobalt (Co) is in +2 oxidation state.
- For `[Mn(H2O)6]^(3+)`: Manganese (Mn) is in +3 oxidation state.

3. **Identify the nature of the ligands**:
- CN⁻ (Cyanide) is a strong field ligand.
- NO2⁻ (Nitrite) is a strong field ligand.
- F⁻ (Fluoride) is a weak field ligand.
- H2O (Water) is a weak field ligand.
- NH3 (Ammonia) is a strong field ligand.

4. **Analyze each complex for spin state**:
- **[Fe(CN)6]^(3-)**: Strong field ligand, low spin (1 unpaired electron).
- **[Co(NO2)6]^(3-)**: Strong field ligand, low spin (0 unpaired electrons).
- **[FeF6]^(3-)**: Weak field ligand, high spin (5 unpaired electrons).
- **[IrF6]^(3-)**: Strong field ligand (due to being a heavier metal), low spin (0 unpaired electrons).
- **[Co(NH3)6]^(3+)**: Strong field ligand, low spin (0 unpaired electrons).
- **[Co(H2O)6]^(2+)**: Weak field ligand, high spin (3 unpaired electrons).
- **[Mn(H2O)6]^(3+)**: Weak field ligand, high spin (4 unpaired electrons).

5. **Count the low spin complexes**:
- Low spin complexes: `[Fe(CN)6]^(3-)`, `[Co(NO2)6]^(3-)`, `[IrF6]^(3-)`, `[Co(NH3)6]^(3+)`.
- Total low spin complexes = 4.

### Final Answer:
The total number of low spin complexes is **4**.