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If alpha != beta but, alpha^(2) = 4alpha...

If `alpha != beta` but, `alpha^(2) = 4alpha - 2 and beta^(2) = 4beta - 2` then the quadratic equation with roots `(alpha)/(beta) and (beta)/(alpha)` is

A

`x^(2) - 4x + 2 = 0`

B

`x^(2) - 6x + 1= 0`

C

`x^(2) + 6x - 1 = 0`

D

`x^(2) + 4x - 2 = 0`

Text Solution

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The correct Answer is:
B
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