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Reduction potentials of four elements P,...

Reduction potentials of four elements P, Q, R, S is `-2.90V, 0.34V, 1.2V and -0.76V`. The decreasing order of reducing power is

A

'P gt Q gt R gt S'

B

S gt R gt Q gt P

C

P gt S gt Q gt R

D

Q gt S gt R gt P

Text Solution

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The correct Answer is:
To determine the decreasing order of reducing power based on the given reduction potentials of elements P, Q, R, and S, we can follow these steps: ### Step 1: Write down the reduction potentials We have the following reduction potentials: - P: -2.90 V - Q: 0.34 V - R: 1.2 V - S: -0.76 V ### Step 2: Understand the relationship between reducing power and reduction potential The reducing power of an element is inversely proportional to its reduction potential. This means that a lower (more negative) reduction potential indicates a stronger reducing agent (higher reducing power). ### Step 3: Identify the order of reduction potentials From the values given: - The most negative potential is for P (-2.90 V), indicating it has the highest reducing power. - The next most negative is S (-0.76 V). - Then, we have Q (0.34 V). - Finally, R has the highest reduction potential (1.2 V), indicating it has the lowest reducing power. ### Step 4: Arrange the elements in decreasing order of reducing power Based on the analysis: 1. P (highest reducing power) 2. S 3. Q 4. R (lowest reducing power) Thus, the decreasing order of reducing power is: **P > S > Q > R** ### Final Answer: The decreasing order of reducing power is P > S > Q > R. ---
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